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3 years ago

Simplify 2 (n+1) + n² + 4 (n-3)

Mathematics

2 answers:

7nadin3 [17]3 years ago

6 0

(n+3)^3 - 19 this is just adding like terms

Gala2k [10]3 years ago

4 0

2 (n+1) + n² + 4 (n-3)
= 2n + 2 + n² + 4n - 12 ...expand by using distributive property
= n² + 6n - 10 ...combine like terms

hope it helps

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2 years ago

Question 1

arlik [135]

Answer:

Step-by-step explanation:

This problem can be done without the Distance Formula (which is a way to find the distance between any two points in the plane).

The attached image shows the points and segments joining them.

PQ = 5 because the points are on the same horizontal line, and you can count spaces between them (or subtract x-coordinates: 4 - (-1) = 5).

PR = 12 because the points are on the same vertical line; count spaces or subtract y-coordinates, 7 - (-5) = 12.

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$(\text{leg})^2+(\text{leg})^2=(\text{hypotenuse})^2$

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3 years ago

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Wewaii [24]

Answer:

The other endpoint is located at (-4,-2)

Step-by-step explanation:

we know that

The diagonals of a rhombus bisect each other

That means-----> The diagonals of a rhombus intersect at the midpoint of each diagonal

The point (0,4) is the midpoint of the two diagonals

The formula to calculate the midpoint between two points is equal to

$M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

we have

$M=(0,4)$

$(x_1,y_1)=(4,10)$

substitute

$(0,4)=(\frac{4+x_2}{2},\frac{10+y_2}{2})$

Find the x-coordinate $x_2$ of the other endpoint

$0=\frac{4+x_2}{2}$

$x_2=-4$

Find the y-coordinate $y_2$ of the other endpoint

$4=\frac{10+y_2}{2}$

$8=10+y_2$

$y_2=-2$

therefore

The other endpoint is located at (-4,-2)

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3 years ago