The number of Hamilton Circuits with 8 vertices are 5040.
Given that, a complete, weighted graph with 8 vertices.
<h3>What are Hamilton Circuits?</h3>
A Hamiltonian circuit is a circuit that visits every vertex once with no repeats. Being a circuit, it must start and end at the same vertex. A Hamiltonian path also visits every vertex once with no repeats, but does not have to start and end at the same vertex.
For N vertices in a complete graph, there will be (n−1)!=(n−1)(n−2)(n−3)…3⋅2⋅1 routes. Half of these are duplicates in reverse order, so there are (n−1)!/2 unique circuits.
A complete graph with 8 vertices would have = 5040 possible Hamiltonian circuits. Half of the circuits are duplicates of other circuits but in reverse order, leaving 2520 unique routes.
Therefore, the number of Hamilton Circuits with 8 vertices are 5040.
Learn more about the Hamilton Circuits here:
brainly.com/question/24725745.
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Answer:
with the keep change flip method
Answer:
51 m^2
Step-by-step explanation:
Draw a vertical line through the roof peak. There is a trapezoid on either side. The average height of the trapezoid is (16 m + 10 m)/2 = 13 m. The width of one trapezoid is 2.5 m. Thus, the area of one trapezoid is
(13 m)(2.5 m) = 32.5 m^2.
There are two such trapezoids, so the combined area is 2(32.5 m^2), or 65 m^2.
Now find the area of the open door: It is (7 m)(2 m) = 14 m^2.
Subtracting this door area from the overall area:
65 m^2 - 14 m^2 = 51 m^2
The answer is B
the steps are these
interchange the x and y variables
x=5y-8
solve for y so we get
y = x+8
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