Two points determine a line. In slope intercept form we have:
y = -2x + b
So:
-12 = -2(3) + b and [first equation]
k = -2(6) + b [second equation]
We have a system of simultaneous equations with two unknowns. The first is trivially easy to solve:
-12 = -6 + b [Evaluate -2(3)]
-6 = b [Add +6 to each side]
So we substitute this into the second equation:
k = -2(6) + -6 = -18
We could double check our work knowing that m=Δy/Δx
We expect m to be -2. Does:
-2 = (-18 - -12)/(6 - 3) = -6/3 = -2?
;)
Check the picture below. Bearing in mind that x = -2 is a vertical line.
Answer:
the relation is NOT a function
domain: {
1,-2,1}
range: {
-2, 0, 2, 3}
Step-by-step explanation:
Answer:
24) x = 9.2
25) x = 30.8
Step-by-step explanation:
Given
See attachment for triangles
Solving (24)
To solve for x, we make use of cosine formula
i.e.
cos(40) = adjacent ÷ hypotenuse
So, we have:
cos(40) = x ÷ 12
Multiply both sides by 12
12 cos(40) = x
12 * 0.7660 = x
x = 9.2
Solving (25)
To solve for x, we make use of sine formula
i.e.
sin(25) = opposite ÷ hypotenuse
So, we have:
sin(25) = 13 ÷ x
Multiply both sides by
x sin(25) = 13
Divide by sin(25)
x = 13 ÷ sin(25)
Using a calculator
x = 30.8