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lina2011 [118]
2 years ago
6

What is the answer to this 2^2x =1/32

Mathematics
2 answers:
Alex73 [517]2 years ago
8 0

Answer:

x=-\frac{5}{2}

Step-by-step explanation:

2^{2x}=\frac{1}{32}

2^{2x}=\frac{1}{2^5}

2^{2x}=2^{-5}

2x=-5

x=-\frac{5}{2}

ryzh [129]2 years ago
3 0

Answer:

x= 1/128

Step-by-step explanation:

Evaluate 2^2x= 1/32

4x=1/32

divide

4x=1/32

4x/4= 1/32/4

simplify

x=1/128

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icating any part of this book is prohibited by law. Solve. 18. EXPLAIN Farzana knows that the additive identity property states
Dahasolnce [82]

Answer:

No, since when you multiply a number by 0, that means you are not adding that number to the sum which is 0. Since there is no addition going on, the answer is 0, so when you multiply any number by 0, the answer is 0.

Step-by-step explanation:

3 0
1 year ago
How do you find the angles on this special triangle?
Rasek [7]

Answer:

it is isosceles triangle with an angle = 90. Two others angle are equal. sum of all angles in triangle is 180.

2x + 90=180 --> x=45

3 0
3 years ago
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Please help, if you answer thanks :) will mark brainliest
nignag [31]

I believe the correct answer is C.

5 0
4 years ago
Let e be the line through A (-4,5) and B (3. t) that is perpendicular to the line through
grigory [225]

Answer:

Step-by-step explanation:

product of slopes of perpendicular lines=-1

(t-5)/(3+4)×(2-3)/(-4-1)=-1

(t-5)/7×(-1/-5)=-1

(t-5)/35=-1

t-5=-1×35=-35

t=-35+5

t=-30

2.

slopes of parallel lines are equal.

(-2+3)/(t-4)=(-1-4)/(4+2)

1/(t-4)=-5/6

t-4=-6/5

t=4-6/5=(20-6)/5=14/5

3.

x>0,y<0

so P lies in4th quadrant.

except cos and sec all are negative.

so only cos and sec are positive.

8 0
3 years ago
If 1900 square centimeters of material are available to make a box with a square base and an open top, find the largest possible
Evgen [1.6K]

Answer:

Volume = 7969 cubic centimeter

Step-by-step explanation:

Let the length of each side of the base of the box  be A and the height of the box be H.

Area of material required to make the box  is equal to  is A^2 + 4*A*H.

A^2 + 4*A*H = 1900

 Rearranging the above equation, we get -  

`H = \frac{(1900 - A^2)}{(4*A)}

Volume of box is equal to product of base area of box and the height of the box -  

V = A*A* H

Substituting the given area we get -

\frac{A^2*(1900 - A^2)}{4A} = \frac{(1900*A - A^3)}{4}

For maximum volume

\frac{dV}{dA} =0

\frac{ 1900}{4} - \frac{3*A^2}{4} = 0

A^2 = \frac{1900}{3}

Volume of the box

= \frac{\frac{1900}{3}*(1900 - \frac{1900}{3}) }{4 * \sqrt{\frac{1900}{3} } }

= 7969 cubic centimeter

3 0
3 years ago
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