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zimovet [89]
4 years ago
6

Will every solid with the same dimensions have the same density? please explain

Physics
1 answer:
g100num [7]4 years ago
4 0
Absolutely not. You can have a piece of wood and water with the same dimensions, but dimensions Won't matter
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A solid weighs 16.5N on the surface of the moon. The force of gravity on the moon is 1.7N/Kg.
Fiesta28 [93]

Answer:

mass = 9.7 kg

Explanation:

Weight = Mass x Acceleration due to gravity (g)

16.5 = mass x 1.7

mass = \frac{16.5}{1.7} = 9.7 kg

3 0
3 years ago
A student gives a brief push to a block of dry ice. A moment later, the block moves across a very smooth surface at a constant s
Monica [59]
Hey There,

Question: "<span>A student gives a brief push to a block of dry ice. A moment later, the block moves across a very smooth surface at a constant speed. When drawing the free body diagram for the block of dry ice moving at a constant speed, the forces that should be included are: (select all that apply)"

Answer: C. Force Of Friction
              B. Force

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7 0
3 years ago
Read 2 more answers
How wind Form?<br> Explain please
snow_lady [41]
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6 0
4 years ago
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A girl is floating in a freshwater lake with her head just above the water. If she weighs 610 N, what is the volume of the subme
Elden [556K]

Answer:

The volume of the submerged part of her body is 0.0622m^{3}

Explanation:

Let's define the buoyant force acting on a submerged object.

In a submerged object acts a buoyant force which can be calculated as :

B=ρ.V.g

Where ''B'' is the buoyant force

Where ''ρ'' is the density of the fluid

Where ''V'' is the submerged volume of the object

Where ''g'' is the acceleration due to gravity

Because the girl is floating we can state that the weight of the girl is equal to the buoyant force.

We can write :

W_{girl}=B (I)

Where ''W'' is weight

⇒ If we consider ρ = 1000\frac{kg}{m^{3}} (water density) and g=9.81\frac{m}{s^{2}} and replacing this values in the equation (I) ⇒

B=W_{girl}

B=610N

ρ.V.g = 610N

1000\frac{kg}{m^{3}}.V.(9.81\frac{m}{s^{2}})=610N (II)

The force unit ''N'' (Newton) is defined as

N=kg.\frac{m}{s^{2}}

Using this in the equation (II) :

(9810\frac{N}{m^{3}}).V =610N

V=\frac{610N}{9810\frac{N}{m^{3}}}

V=0.0622m^{3}

We find that the volume of the submerged part of her body is 0.0622m^{3}

8 0
4 years ago
1. To calulate the molarity of a solution, you need to know the moles of the solute and the?
Fofino [41]
1. Volume of the solution (B)

2. Celery (D)

3. Hydroxide ions in solution (A)
3 0
3 years ago
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