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prohojiy [21]
2 years ago
11

Open the attached file. It shows 2 waves (a blue one and an orange one) that are moving through the same medium at the same time

. Your challenge is to DRAW the RESULTANT wave and LABEL the areas of interference with CI, DI and/or points of TDI.

Physics
1 answer:
Taya2010 [7]2 years ago
3 0

The diagram is labelled to DRAW the RESULTANT wave and LABEL the areas of interference with CI, DI and/or points of TDI.

<h3>What is refraction?</h3>

When a light ray falls on the interface of two medium like air and water, then the portion of light is reflected and another portion of the light is refracted into the water medium. The angle of incidence is equal to the angle of reflection but the angle of incidence is larger then the angle of refraction.

Open the attached file. It shows 2 waves (a blue one and an orange one) that are moving through the same medium at the same time.

Thus, the diagram is labelled.

Learn more about refraction.

brainly.com/question/14760207

#SPJ1

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Problem: Hooke's law states that the force on a spring varies directly with the distance that it is stretched. If a spring has a
Scorpion4ik [409]

Answer:

Restoring force of the spring is 50 N.

Explanation:

Given that,

Spring constant of the spring, k = 100 N/m

Stretching in the spring, x = 0.5 m

We need to find the restoring force of the spring. It can be calculated using Hooke's law as "the force on a spring varies directly with the distance that it is stretched".

F=kx

F=100\ N/m\times 0.5\ m

F = 50 N

So, the restoring force of the spring is 50 N. Hence, this is the required solution.

7 0
4 years ago
Professional baseball pitchers deliver pitches that can reach the blazing speed of 100 mph (miles per hour). A local team has dr
Wittaler [7]

Answer:

A. ) K =126. 7 J

B. ) h= 91.1 m.

Explanation:

A)

  • Assuming no air resistance, once released by the pitcher, the speed must keep constant through all the trajectory, so the kinetic energy of the ball can be expressed as follows:

       K = \frac{1}{2}*m*v^{2}  =  \frac{1}{2}*0.142 kg*(42.24m/s)^{2} = 126.7 J (1)

B)

  • Neglecting air resistance, total mechanical energy must be the same at any point, so, if we choose the ground level as the zero reference level for the gravitational potential energy, and assuming that the ball attains this kinetic energy just before striking ground, this value must be equal to the gravitational potential energy just before be dropped, so we can write the following equality:

        U_{o} = K_{f} = 126. 7 J (2)

        ⇒ m*g*h = 126. 7 J

  • Solving for h, we get:

       h = \frac{K_{f}}{m*g} = \frac{126.7J}{0.1420kg*9.8m/s2} = 91.1 m (3)

4 0
3 years ago
Elastic and inelastic collisions
Virty [35]

Explanation:

A perfectly elastic collision is defined as one in which there is no loss of kinetic energy in the collision. An inelastic collision is one in which part of the kinetic energy is changed to some other form of energy in the collision.

5 0
3 years ago
In a circuit of 2 lamps in parallel if the current in one lamp is 2a the current in the other lamp is?
ioda

In a circuit having 2 lamps are connected in parallel to a battery

then the two lamps will be having the same potential as the battery

i.e

V_{1} = V_{2} = V_{battery}

As per Ohm's law,

I_{1} = \frac{V_{1}}{R_{1}} and I_{2} = \frac{V}{R_{2} }

In other words, each lamp's current is inversely related to its individual resistance. We only know the current in one of the bulbs in this specific instance. We would therefore need further information in order to calculate the current in the other light. Therefore, there isn't enough data to make a statement.

Under the assumption that all physical parameters, including temperature, remain constant, Ohm's law asserts that "the voltage across a conductor is directly proportional to the current flowing through it".

Learn more about Ohm's law here

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4 0
2 years ago
A 10.0kg water balloon is dropped from a height of 12.0m. Calculate the speed of the balloon just before it hits the ground
kolbaska11 [484]

Answer:

15.5 m/s.

Explanation:

Potential energy of the balloon has been converted to kinetic energy.

potential energy = kinetic energy.

mgh = ½mv².

10* 10* 12= ½ *10 *v²

1200 = 5v²

v²=1200÷5

v=√240

v= 15.49~15.5 m/s.

5 0
3 years ago
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