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3 years ago

Which is a characteristic of all waves?

Physics

2 answers:

juin [17]3 years ago

7 0

Answer:à

Explanation:waves carry energy in the direction in which they move

kramer3 years ago

4 0

Characteristics of all waves:

All waves carry energy.

All waves move through space.

All waves move through matter, from particle to particle.

All waves transfer energy parallel to the direction of wave mo tion.

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Tides are caused by the force of gravity from the sun and moon acting on Earth.

vfiekz [6]

Yes that answer is correct because sometimes tides cause waves to happen

4 0

3 years ago

Read 2 more answers

A 4.0 cm × 4.2 cm rectangle lies in the xy-plane. You may want to review (Pages 664 - 668) . Part A What is the electric flux th

padilas [110]

Answer:

(A). The flux is 0.336 N.m²/C

(B). The flux is zero.

Explanation:

Given that,

Length = 4.2 cm

Width = 4.0 cm

Electric field $E=(150 i-200 k)\ N/C$

Area vector is perpendicular to xy plane

(A). We need to calculate the flux

Using formula of flux

$\phi=E\cdot A$

Where, E = electric field

A = area

Put the value into the formula

$\phi=(150 i-200 k)\times(4.2\times10^{-2}\times4.0\times10^{-2})k$

$\phi=-200\times4.2\times10^{-2}\times4.0\times10^{-2}$

$\phi=-0.336\ N.m^2/C$

(B). Given electric field

$E=(150i-200j)\ N/C$

We need to calculate the flux

Using formula of flux

$\phi=E\cdot A$

Put the value into the formula

$\phi=(150 i-200 j)\times(4.2\times10^{-2}\times4.0\times10^{-2})k$

Here, The component of k is not given

So, the flux is

$\phi=0$

Hence, (A). The flux is -0.336 N.m²/C

(B). The flux is zero.

7 0

3 years ago

Read 2 more answers

In the circuit shown, the galvanometer shows zero current. The value of resistance R is :

Tasya [4]

Answer:

its supposed to be (a) 1W

8 0

3 years ago

an object is thrown into the air with an initial velocity of 12 meters per seconds from a platform that is raised 4 meters above

butalik [34]

Answer:

1.52 seconds

Explanation:

Step 1: identity the given parameters

Initial velocity (u) = 12m/s

Height above ground (h1) = 4m

Final velocity (V) = 0

Step 2: calculate the height travelled by the object from 4m height (h2).

V^2 = U^2 -2gh

0= 12^2-2(9.8*h)

2(9.8*h) = 12^2

19.6*h = 144

h = 144/19.6

h = 7.347 m

Total height above ground (ht) = 4m +7.347m = 11.347m

Step 3: calculate the time reach ground

T = √(2h/g)

T = √(2*11.347/9.8)

T= √(22.694/9.8)

T= √2.316

T= 1.52 seconds

8 0

3 years ago

Electricity can travel in a(n) _______ circuit. closed open short electromagnetic

satela [25.4K]

Electricity can travel in a closed circuit.

7 0

3 years ago