Answer:
you will get a decimal answer which is 94.10526316
Step-by-step explanation:
We have to simplify
sec(θ) sin(θ) cot(θ)
Now first of all let's simplify these separately , using reciprocal identities.
Sec(θ) = 1/cos(θ)
Sin(θ) is already simplified
Cot(θ)= cos(θ) / sin(θ) ,
Let's plug these values in the expression
sec(θ) sin(θ) cot(θ)
= ( 1/cos(θ) ) * ( sin(θ) ) * ( cos(θ) / sin(θ) )
= ( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )
sin cancels out with sin and cos cancels out with cos
So , answer comes out to be
=( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )
= 1
Answer:
- See the graphs attached and the explanation below
Explanation:
The most simple sine function, considered the parent function, is:

That function has:
- Midline, also known as rest or equilibrium position: y = 0
- Minimum: - 1
- Maximum: 1
- Amplitude: the distance between a minimum or a maximum and the midline = 1
- period: the interval of repetition of the function = 2π
The more general sine function is:

That function has:
- Midline: y = D (it is a vertical shift from the parent function)
- Minimum: - A + D
- Maximum: A + D
- Amplitude: A
- period: 2π/B
- phase shift: C (it is a horizontal shift of the from the parent function)
Now, you have to draw the sine function with the given key features:
- Period = 4 ⇒ 2π/B = 4 ⇒ B = π/2
- midline y = - 1 ⇒ D = - 1
Substitute the know values and use the y-intercept to find C:

Substitute (0, -1)

Hence, the function to graph is:

To draw that function use this:
- Maxima: 3(1) - 1 = 3 - 1 = 2, at x = 1 ± 4n (n = 0, 1, 2, 3, ...)
- Minima: 3(-1) - 1 = - 3 - 1 = -4
- y-intercept: (0, - 1)
- x-intercepts: the solutions to 0 = 3sin(πx/2) = - 1
- first point of the midline: (0, -1) it is the same y-intercept
With that you can understand the graphs attached.
Answer:

Step-by-step explanation:
Q) 5 × (4/9) = ?
→ (5 × 4)/9
→ 20/9

The function is definately defined at x=0 but not x=1.
But its just one part of the coordinate (x,y).
If the value of y or f(x) is considered, you'll see that it is never possible to attain f(x)=0. In other terms (x,y)= (0,0) is not a defined point in the graph of the function because the graph doesnt pass through that point.
Now I hope you understood what I meant!
Conclusion- The above function is not defined at all points in the space having the abscissa or x=1 in the coordinate and also at ordinate or y=0 in the coordinate.nation: