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myrzilka [38]
3 years ago
12

How long did it take to reach the bottom of the slope

Mathematics
1 answer:
mafiozo [28]3 years ago
3 0
To solve this we are going to use the kinematic equation for final velocity: V_{f}=V_{i}+at
where
V_{f} is the final velocity
V_{i} is the initial velocity 
a is the acceleration 
t is the time

We know for our problem that the the velocity at the beginning of the slope is  2.0ms^{-1}, so V_{i}=2.0. We also know that the speed ad the bottom of the slope is 20ms^{-1}, so V_{f}=20. We also know that the acceleration is 6ms^{-2}, so a=6. Lets replace those values in our formula and solve for t:
V_{f}=V_{i}+at
20=2+6t
6t=18
t= \frac{18}{3}
t=3 seconds

We can conclude that it takes the roller coaster 3 seconds to reach the bottom of the slope.
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A farmer has a collapsable grain bag which can expand both vertically and horizontally as he needs it to. He wants to find a fun
bija089 [108]

Answer:

3x^{3}+15x^{2}+x+5

Step-by-step explanation:

We are told that the area of the bag can be represented by the function f(x)=3x^{2} +1 and as the bag is raised up its height can be represented by the function g(x)=x +5.

Since we know that we can find volume of cuboid by multiplying base area to its height. We are given area and height of bag as functions. Now we will find volume of the bag by multiplying these functions.  

\text{Volume of collapsible bag}=f(x)*g(x)  

\text{Volume of collapsible bag}=(3x^{2}+1)*(x +5)

After using distributive property we will get,

\text{Volume of collapsible bag}=3x^{2}(x+5)+1(x+5)

\text{Volume of collapsible bag}=3x^{3}+15x^{2}+x+5

Therefore, the collapsible bag can hold 3x^{3}+15x^{2}+x+5 grain.

6 0
3 years ago
Is this statement true or false 8/15 < 3/5
gayaneshka [121]
TRUE because 8/15 = 0.53 which is less than 3/5 = 0.60
7 0
3 years ago
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4 0
3 years ago
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marysya [2.9K]

Answer:

a

Step-by-step explanation:

5 0
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3 years ago
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