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myrzilka [38]
3 years ago
12

How long did it take to reach the bottom of the slope

Mathematics
1 answer:
mafiozo [28]3 years ago
3 0
To solve this we are going to use the kinematic equation for final velocity: V_{f}=V_{i}+at
where
V_{f} is the final velocity
V_{i} is the initial velocity 
a is the acceleration 
t is the time

We know for our problem that the the velocity at the beginning of the slope is  2.0ms^{-1}, so V_{i}=2.0. We also know that the speed ad the bottom of the slope is 20ms^{-1}, so V_{f}=20. We also know that the acceleration is 6ms^{-2}, so a=6. Lets replace those values in our formula and solve for t:
V_{f}=V_{i}+at
20=2+6t
6t=18
t= \frac{18}{3}
t=3 seconds

We can conclude that it takes the roller coaster 3 seconds to reach the bottom of the slope.
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3 years ago
Maria borrowed $120,000 from a bank when she bought her co-op for $156,000.
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2 years ago
According to a study done by De Anza students, the height for Asian adult males is normally distributed with an average of 66 in
Zolol [24]

Answer:

The probability that the person is between 65 and 69 inches is 0.5403

Step-by-step explanation:

Mean height = \mu = 66

Standard deviation = \sigma = 2.5

We are supposed to find What is the probability that the person is between 65 and 69 inches i.e.P(65<x<69)

Z=\frac{x-\mu}{\sigma}

At x = 65

Z=\frac{65-66}{2.5}

Z=-0.4

Refer the z table for p value

P(x<65)=0.3446

At x = 69

Z=\frac{69-66}{2.5}

Z=1.2

P(x<69)=0.8849

So,P(65<x<69)=P(x<69)-P(x<65)=0.8849-0.3446=0.5403

Hence the probability that the person is between 65 and 69 inches is 0.5403

6 0
3 years ago
Find the 7th term of the geometric sequence whose common ratio is 1/3 and whose first term is 5.
wolverine [178]

Answer:

t_7 =\frac{5}{729}

Step-by-step explanation:

We are given that:

First term (a) = 5

common ratio (r) =\frac{1}{3}

The nth term of a geometric sequence is given as:

t_n =ar^{n-1} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{7-1} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{6} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{6} \\\therefore t_7 =5\times \frac{1}{729}\\\\\huge\red{\boxed{\therefore t_7 =\frac{5}{729} }}

8 0
3 years ago
What is the area of the sector a.) 10π cm^2b.) 16π cm^2c.) 40π cm^2d.) 64π cm^2
Natalija [7]

Answer:

C. 40π cm²

Explanation:

• The central angle of the sector = 225 degrees

,

• The radius of the sector = 8cm

For a sector of radius r and central angle θ, we calculate the area using the formula below:

\text{Area}=\frac{\theta}{360\degree}\times\pi r^2

Substituting the given values, we have:

\begin{gathered} \text{Area}=\frac{225}{360}\times\pi\times8^2 \\ =\frac{5}{8}\times64\times\pi \\ =5\times8\times\pi \\ =40\pi cm^2 \end{gathered}

The area of the sector is 40π cm².

3 0
1 year ago
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