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Elena L [17]
3 years ago
11

What is the rule for the sum of angles?

Mathematics
2 answers:
Greeley [361]3 years ago
8 0

Answer: Memorise the rule that the sum of the interior angles of a polygon = (n-2) × 180°, and that each interior angle of a regular polygon can be calculated by the rule: (n-2) × 180° / n, where 'n' refers to the number of sides.

Step-by-step explanation:

Roman55 [17]3 years ago
6 0

Step-by-step explanation:

remeber this rule

sum=(n-2)*180°

n is no of side

take that away from 2

multiply 180

e.g triangle

3 sides

take away 2

3-2 is 1.

multiply by 180

1*180 is 180°

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Solve the inequality. x + 7 > 11 A. x> 18 B. x> −4 C. x > 4 D. x> −18
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c. x>4

Step-by-step explanation:

subtract 7 from both sides. 11-7=4

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Tamora just made the last of her monthly payments on her loan. She had been making these payments for the past nine years. The l
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Detailed Solution: 
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additional $939.25 was paid in service charges.
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the half life of c14 is 5730 years. Suppose that wood found at an archeological excavation site contains about 35% as much C14 a
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Answer:

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

\frac{dm}{dt} = -\frac{m}{\tau} (Eq. 1)

Where:

\frac{dm}{dt} - First derivative of mass in time, measured in miligrams per year.

\tau - Time constant, measured in years.

m - Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

\int {\frac{dm}{m} } = -\frac{1}{\tau}\int dt

\ln m = -\frac{1}{\tau} + C

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (Eq. 2)

Where:

m_{o} - Initial mass of isotope, measured in miligrams.

t - Time, measured in years.

And time is cleared within the equation:

t = -\tau \cdot \ln \left[\frac{m(t)}{m_{o}} \right]

Then, time constant can be found as a function of half-life:

\tau = \frac{t_{1/2}}{\ln 2} (Eq. 3)

If we know that t_{1/2} = 5730\,yr and \frac{m(t)}{m_{o}} = 0.35, then:

\tau = \frac{5730\,yr}{\ln 2}

\tau \approx 8266.643\,yr

t = -(8266.643\,yr)\cdot \ln 0.35

t \approx 8678.505\,yr

The wood was cut approximately 8679 years ago.

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