4 years ago

Two sides of a triangle measure 10cm and 15cm. which measure is possible for the third side

Mathematics

1 answer:

Irina-Kira [14]4 years ago

6 0

The measurement for the third side is 155 cm. Hope this helps! Mark my answer brainliest when u can please thx

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8(x+1)-7x ≥-3 help me find the solution

Ann [662]

Answer:

x $\geq$ 11

Step-by-step explanation:

$8\left(x+1\right)-7x$

$8x+8-7x$

$x+8$

Then..

$x+8\ge \:-3$

Subtract 8 from both sides

$x+8-8\ge \:-3-8$

Then, you got your awnser.

$x\ge \:-11$

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3 years ago

How do I solve this?

antiseptic1488 [7]

Answer:

x= -2

Step-by-step explanation:

y=x+4

y=2

2=x+4

-4+2=x

-2=x

x=-2

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3 years ago

Read 2 more answers

Please show me how to solve for Xsquared - 21.75X = -15.75. I have the solution but do not know how to solve it.

Andreas93 [3]

$x^2-21.75x=-15.75 \\
x^2-21.75x+15.75=0$

Use the quadratic formula:
$x^2-21.75x+15.75=0 \\ \\
a=1 \\ b=-21.75 \\ c=15.75 \\ b^2-4ac=(-21.75)^2-4 \times 1 \times 15.75=473.0625-63=410.0625 \\ \\
x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-(-21.75) \pm \sqrt{410.0625}}{2 \times 1}=\frac{21.75 \pm 20.25}{2} \\
x=\frac{21.75-20.25}{2} \ \lor \ x=\frac{21.75+20.25}{2} \\
x=\frac{1.5}{2} \ \lor \ x=\frac{42}{2} \\
x=\frac{15}{20} \ \lor \ x=21 \\
x=\frac{3}{4} \ \lor \ x=21 \\
\boxed{x=\frac{3}{4} \hbox{ or } x=21}$

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sergejj [24]

Step-by-step explanation:

Transitive property of Angle Congruence

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