Slope of line = tan(120) = -tan(60) = - √3
Distance from origin = 8
Let equation be Ax+By+C=0
then -A/B=-√3, or
B=A/√3.
Equation becomes
Ax+(A/√3)y+C=0
Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/√3)y+C)/sqrt(A^2+(A/√3)^2))
Substitute coordinates of origin (x,y)=(0,0) =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/√(4/3) => C=8*2/√3 = (16/3)√3
Therefore one solution is
x+(1/√3)+(16/3)√3=0
or equivalently
√3 x + y + 16 = 0
Check:
slope = -1/√3 .....ok
distance from origin
= (√3 * 0 + 0 + 16)/(sqrt(√3)^2+1^2)
=16/2
=8 ok.
Similarly C=-16 will satisfy the given conditions.
Answer The required equations are
√3 x + y = ± 16
in standard form.
You can conveniently convert to point-slope form if you wish.
Answer:
x = $3, or x = $11
Step-by-step explanation:
The equation given is 
where
- P(x) is the profit, and
- x is the app price
<u>We want app prices (x's) when profit (P(x)) is 0, so plugging in into the equation:</u>
<em>It means (x-3) = 0 OR (x-11) = 0</em>
So, x = 3, or 11
Answer:
7. Slope = -5
Y-intercept = -3/4
8. Slope = 1/4
Y-intercept = 5
Step-by-step explanation:
y = mx + b
Slope = m
Y-intercept = b
Answer:
C
You just split the equation, as the brackets are both same. If you take (x-6) out, it will leave you with 3x+8.
Therefore, (x-6)(3x+8) is the answer.
The ratio of their areas is the square of whatever number was supposed to appear afrer the phrase "... in the ratio of ".
