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nadya68 [22]
2 years ago
5

Solve for x. Enter the solutions from least to greatest. . (x - 10)2 - 1 = 0

Mathematics
1 answer:
lawyer [7]2 years ago
4 0
2x -20 -1 =0
2x -21=0
2x=21
x= 10.5
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X/4 + 9 = x ? A)12, B)14, C)10, D)5​
Eddi Din [679]

Answer:

A) 12.

Step-by-step explanation:

Plug in 12 for x in the given equation:

x/4 + 9 = x

(12)/4 + 9 = 12

Simplify. Remember to follow PEMDAS. First, divide, then add:

(12/4) + 9 = 12

(3) + 9 = 12

12 = 12 (True).

~

5 0
3 years ago
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17. What unit of time will make the statement true?<br> seconds + seconds x day = seconds ?
inna [77]

Answer:

seconds could be anything but day was 0 then there would be no seconds, right??? that would basically be true.

Step-by-step explanation:

8 0
3 years ago
PLEASE HELP<br> 2n-200 but n = 150
hram777 [196]

Answer:

Just plug in where n is= 150 then solve the answer is 100

Step-by-step explanation:

2(150)-200

7 0
3 years ago
Read 2 more answers
A
Musya8 [376]

Answer:

y = -4x - 16 or y +4x + 16 = 0

Step-by-step explanation:

Gradient (m) = -4

Equation of a line given gradient and one point=

y - <em>y </em>= m(x - <em>x)</em><em> </em>where (<em>x </em>, <em>y </em>) are the coordinates of the point.

Substituting...

y -(-4) = -4(x -(-3))

y + 4 = -4(x + 3)

y + 4 = -4x - 12

y = -4x - 12 - 4

y = -4x - 16 or y +4x + 16 = 0

6 0
3 years ago
A broth used to manufacture a pharmaceutical product has its sugar content, in mg/mL, measured several times on each of three su
snow_tiger [21]

Answer:

Yes

Step-by-step explanation:

To compare the variability of the measured sugar content for each day, we can estimate the standard deviation using the Range rule.

Standard Deviation =\dfrac{\text{Maximum Value-Minimum Value}}{4}

Day 1

5.0, 4.8, 5.1, 5.1, 4.8, 5.1, 4.8, 4.8, 5.0, 5.2, 4.9, 4.9, 5.0

  • Maximum Value=5.2
  • Minimum Value=4.8

Standard Deviation =\dfrac{5.2-4.8}{4}

=0.1

Day 2

5.8, 4.7, 4.7, 4.9, 5.1, 4.9, 5.4, 5.3, 5.3, 4.8, 5.7, 5.1, 5.7

  • Maximum Value=5.8
  • Minimum Value=4.7

Standard Deviation =\dfrac{5.8-4.7}{4}

=0.275

Day 3

6.3, 4.7, 5.1, 5.9, 5.1, 5.9, 4.7, 6.0, 5.3, 4.9, 5.7, 5.3, 5.6

  • Maximum Value=6.3
  • Minimum Value=4.7

Standard Deviation =\dfrac{6.3-4.7}{4}

=0.4

Since the estimated standard deviation of the third day is higher than that of the second day, the variability of the process is greater on the third day than on the second day.

4 0
3 years ago
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