If the equation of a circle is (x + 4)2 + (y - 6)2 = 25, its radius is

1 answer:

6 0

Equation fo a circle:
Data:
Center: C(x₀,y₀).
radius: r

(x-x₀)²+(y-y₀)²=r²

In this equation:
(x+4)²+(y-6)²=25
C(-4,6)
r²=25 ⇒r=√25=5

Then, it´s radius is 5.

If, we have got two points:
A(x₁,y₁)
B(x₂,y₂)
The distance beetween the points is:
dist(A,B)=√[(x₂-x₁)²+(y₂-y₁)²]

Then:
A(-6,7)
B(-1,-5)

dist(A,B)=√[(-1+6)²+(-5-7)²]
dist (A,B)=√(5²+12²)
dist (A,B)=√(25+144)
dist (A,B)=√169
dist (A,B)=13

the distance between the points (-6,7) and (-1,-5) is 13.

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3 years ago

6- 6x^2- 3x = 0 solve

VARVARA [1.3K]

Answer:

The solutions are $x=\frac{3)+\sqrt{153} }{-12}$ , $x=\frac{3)-\sqrt{153} }{-12}$

If you need to have them in a decimal form rounded to 3 decimals, the answers would be $x=-1.281$ , $x=0.781$

Step-by-step explanation:

We are given the equation $6-6x^2-3x=0$

The first thing that can be done is to rearrange the terms so that they are in descending order of power. This makes it easier to work with

This gives us $-6x^2-3x+6=0$

To find the solutions to this equation, we can use the quadratic formula, which will tell us that the solutions are equal to $\frac{-b+\sqrt{b^2-4ac} }{2a} ,\frac{-b-\sqrt{b^2-4ac} }{2a}$