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Alex17521 [72]
3 years ago
9

Write the first ten terms of a sequence whose first term is -10 and whose common difference is -2.

Mathematics
1 answer:
Nesterboy [21]3 years ago
3 0
Add the common difference to a term to get the next term.
-10
-10 + (-2) = -12
-12 + (-2) = -14
etc.

The sequence is
-10, -12, -14, -16, -18, -20, -22, -24, -26, -28
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consider the function f(x) = x2 2x – 15. what are the x-intercepts of the function? left-most x-intercept: ( , 0) right-most x-i
eimsori [14]

we have

f(x)=x^{2} +2x-15

we know that

The x-intercept is the value of x when the value of the function is equal to zero

so

in this problem

Find the roots of the function

equate the function to zero

x^{2} +2x-15=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2} +2x=15

Complete the square. Remember to balance the equation by adding the same constants to each side

x^{2} +2x+1=15+1

x^{2} +2x+1=16

Rewrite as perfect squares

(x+1)^{2}=16

Square root both sides

(x+1)=(+/-)\sqrt{16}

(x+1)=(+/-)4

x=-1(+/-)4

x1=-1+4=3

x2=-1-4=-5

x^{2} +2x-15=(x-3)(x+5)

therefore

<u>the answer is</u>

the x-intercepts are the points (3,0) and (-5,0)

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3 years ago
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Ket [755]
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Answer:

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Step-by-step explanation:

Multiply $143 and 12%

Make 12% as decimal: 0.12

143*0.12

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