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nordsb [41]
3 years ago
14

Write an equation of the line that passes through (0,-5) and (-5,-5).

Mathematics
2 answers:
vaieri [72.5K]3 years ago
4 0

Answer:

let me ask on brainly (btw you should check it very great to ask questions)

Step-by-step explanation:

Aleksandr-060686 [28]3 years ago
3 0
Y equal negative 5 (y=-5)
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Solve the binomial (3x-2)^2​
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x=2/3  double zero

Step-by-step explanation:

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2 years ago
A car travels 15 miles per gallon of
Arlecino [84]

Answer:

15x = y

Step-by-step explanation:

15 times the gallons of gas =  miles

15x = y

5 0
3 years ago
A pharmacist has 30% and 60% iodine solutions on hand. How many liters of each iodine solution will be required to produce 6 lit
kkurt [141]

Answer:

4 liters of 60% solution; 2 liters of 30% solution

Step-by-step explanation:

I like to use a simple, but effective, tool for most mixture problems. It is a kind of "X" diagram as in the attachment.

The ratios of solution concentrations are 3:6:5, so I've used those numbers in the diagram. The constituent solutions are on the left; the desired mixture is in the middle, and the numbers on the other legs of the X are the differences along the diagonals: 6 - 5 = 1; 5 - 3 = 2. This tells you the ratio of 60% solution to 30% solution is 2 : 1.

These ratio units (2, 1) add to 3. We want 6 liters of mixture, so we need to multiply these ratio units by 2 liters to get the amounts of constituents needed. The result is 4 liters of 60% solution and 2 liters of 30% solution.

_____

If you're writing equations, it often works well to let the variable represent the quantity of the greatest contributor—the 60% solution. Let the volume of that (in liters) be represented by v. Then the total volume of iodine in the mixture is ...

... 0.60·v + 0.30·(6 -v) = 0.50·6

... 0.30v = 0.20·6 . . . . subtract 0.30·6, collect terms

... v = 6·(0.20/0.30) = 4 . . . . divide by the coefficient of v

4 liters of 60% solution are needed. The other 2 liters are 30% solution.

6 0
3 years ago
GIVING BRANLIEST
Alex_Xolod [135]

Answer:

(4,4)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Perform the indicated operations. Write the answer in standard form, a+bi.<br> (5 + 6i)(5 - 6i)
lubasha [3.4K]

\boxed{\underline{\bf \: ANSWER}}

\sf \: ( 5 + 6 i ) ( 5 - 6 i )

Multiply complex numbers 5+6i and 5-6i in the same way as you multiply binomials.

\dashrightarrow \sf 5\times 5+5\times \left(-6i\right)+6i\times 5+6\left(-6\right)i^{2}

By definition, i² is -1.

\dashrightarrow \sf 5\times 5+5\times \left(-6i\right)+6i\times 5+6\left(-6\right)\left(-1\right)

Do the multiplications.

\dashrightarrow \sf \: 25-30i+30i+36

Now cancel -30i & +30i

\dashrightarrow \sf \: 25 \:  \bcancel{- 30i}  \:  +  \: \bcancel{30i}+36

Now the equation becomes

\dashrightarrow \sf \: 25 \:  + 36 \\ \dashrightarrow  \boxed{\bf \: 61}

________

Hope it helps.

ŕάίήвόώşάĻţ2²2²

5 0
3 years ago
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