Question

In right triangle ABC, AB = 10, AC = 6 and BC = 8 units. What is the distance from C to the midpoint of segment AB?

Answer 1

Midpoint of AB is obviously 5 because its asking for half of the line .
Then layout the triangle as shown in the diagram .
then use Pythagoras theorem which is the hypotenuse squared is equal to the 2 shorter legs squared.
c2=a2+b2
c2=5^2+6^2
c2=25+36
c2=61
c=square root of 61

Answer 2

Using herons formula you find the area
s=24/2=12
$A=\sqrt{s(s-a)(s-b)(s-c)}$
A=24
and A=0.5 base height
sp
24=0.5 (base=AB=10)(height=c to the midpoint of segment AB)
24=5(height)
$\frac{24}{5}$=height