For vertical asymptotes, find the values which make the function indetermine in this case x=-7,so this is the only vertical asymptote.
For horizontal asymptotes, find the limit when x tends to infinity:
=(5x/x-15/x)/(2x/x+14/x) = 5/2, this is the horizontal asymptote y=5/2
For obliques, you have to meet the degree of the numerator is exactly a greater degree than the denominator, in this case they are the same degree so no oblique asymptote.
Answer:
In AMNO, n = 92 inches, N=119° and 20=20°. Find the length of m, to the nearest 10th of an inch In AJKL, j = 9.6 inches, k = 6.4 inches and I=8.4 inches. Find the measure of K to thelaearest degree. In AQRS. q = 49 cm, 7.1 cm and S=70°. Find the area of AQRS, to the nearest 10th of a square centimeter Find all angles, 0 = 0 < 360°, that satisfy the equation below, to the nearest 10th of a degree. 25 sino-1=0 Find all angles, 0 SC <360°, that satisfy the equation below, to the nearest tenth of a degree (if necessary). 12 sin C + 6 = 5 sin ( + 6
Step-by-step explanation:
The answer is A. -8
(step by step)
Do multiplication first. 7 * -8 = -56
Now subtraction. -56 - (-8) = -48
Hope this helped! ☺♥
Answer:
Step-by-step explanation:
Slope
(2, 5) and (14, -4)
_______________
When we solve for slope within two points, we have to follow the formula of slope.
X and Y - The first and second number in both points
1 and 2 - The first or second number within one point
Substitute :
Simplify :
Answer:
20 icnhes
Step-by-step explanation:
not rlly
