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dusya [7]
3 years ago
9

Really easy question I’m Just really tired

Mathematics
1 answer:
alex41 [277]3 years ago
4 0

Answer:

4.5

Step-by-step explanation:

So the ladder is 4 feet from the wall and 18 feet tall. This can translate to negative 4 spaces on the x-axis and 18 spaces on the y-axis. The slope of a line is rise over run which is 18/4 or 4.5

I hope the answer is right and I hope I helped. Have fun with the rest of your math :)

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For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f
butalik [34]

\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k

Let

\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k

The curl is

\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)

where \partial_\xi denotes the partial derivative operator with respect to \xi. Recall that

\vec\imath\times\vec\jmath=\vec k

\vec\jmath\times\vec k=\vec i

\vec k\times\vec\imath=\vec\jmath

and that for any two vectors \vec a and \vec b, \vec a\times\vec b=-\vec b\times\vec a, and \vec a\times\vec a=\vec0.

The cross product reduces to

\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

\nabla\times\vec f=\vec0

which means \vec f is indeed conservative and we can find f.

Integrate both sides of

\dfrac{\partial f}{\partial y}=2xze^{2xyz}

with respect to y and

\implies f(x,y,z)=e^{2xyz}+g(x,z)

Differentiate both sides with respect to x and

\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}

2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}

4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}

\implies g(x,z)=4\sin(xz^2)+h(z)

Now

f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)

and differentiating with respect to z gives

\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}

2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}

\dfrac{\mathrm dh}{\mathrm dz}=0

\implies h(z)=C

for some constant C. So

f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C

3 0
4 years ago
Tammi deposited $520 into a bank account that earned simple interest each year. After 5 years, she had earned $156 in interest.
Sveta_85 [38]

Answer:

6%

Step-by-step explanation:

Interest = Principal * rate * time

      156 = 520(r)(5)

      156 = 2600r

           r = 0.06 or 6%

6 0
3 years ago
Read 2 more answers
Help!! This doesn't make any sense to me. Can anyone help me solve for the value of x?
notsponge [240]
<em>Exterior angle of the triangle is equal to the sum of the opposite angles.</em>

9x = 5x + 9 + x

<em>Combine like terms:</em>
9x = 6x + 9

<em>Take away 6x from both sides:</em>
3x = 9

<em>Divide by 3 on both sides:</em>
x = 3

Answer: x = 3
6 0
3 years ago
What is the MAD of this data ? Round to the nearest hundredth. 7, 14, 15, 9, 11, 14, 11, 10, 17​
Vladimir79 [104]
<h2>2.67</h2>

Step 1 :

Find the mean of the data :

(2+4+6+8) / 4 = 20/4 = 5

Step 2 :

Find the distance between each data and mean.

Distance between 2 and 5 is 3

Distance between 4 and 5 is 1

Distance between 6 and 5 is 1

Distance between 8 and 5 is 3

Step 3 :

Add all the distances :

3+1+1+3 = 8

Step 4 :

Divide it by the number of data :

8 / 4 = 2

2 is the average absolute deviation.

<h2>So hence, your answer is 2.67</h2>

"The beautiful thing about learning is that no one can take it away from YOU"

B.B.King

3 0
2 years ago
Work out the percentage change when a price of £50 is decreased to £40.
Ivanshal [37]
So the formula for price change is amount of change / original price * 100
50-40
= 10
10/50*100
= 1/5*100
= 20%
6 0
3 years ago
Read 2 more answers
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