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dusya [7]
3 years ago
9

Really easy question I’m Just really tired

Mathematics
1 answer:
alex41 [277]3 years ago
4 0

Answer:

4.5

Step-by-step explanation:

So the ladder is 4 feet from the wall and 18 feet tall. This can translate to negative 4 spaces on the x-axis and 18 spaces on the y-axis. The slope of a line is rise over run which is 18/4 or 4.5

I hope the answer is right and I hope I helped. Have fun with the rest of your math :)

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The net of a square pyramid is shown in the diagram.
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Answer:

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$43.68532 rounded to the nearest dollar is?
Sedaia [141]

Note that when rounding, if the number is:

5 or greater, round up

4 or less, round down

43.68532 rounded to the nearest dollar is 44, as 6 rounds up

$44 is your answer

hope this helps

8 0
2 years ago
B + (4 - a) x 9 = ???
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Solve the following system using substitution.
ziro4ka [17]

Answer/Step-by-step explanation:

3. By substitution method, let's substitute \frac{2}{3}x- 4 for y in the first equation.

Thus,

\frac{1}{3}x + 2(\frac{2}{3}x- 4) = 1

Solve for x

\frac{x}{3} + \frac{4x}{3} - 4 = 1

Add 4 to both sides

\frac{x}{3} + \frac{4x}{3} - 4 + 4 = 1 + 4

\frac{x}{3} + \frac{4x}{3} = 5

\frac{x + 4x}{3} = 5

\frac{5x}{3} = 5

Multiply both sides by 3

\frac{5x}{3}*3 = 5*3

5x = 15

Divide both sides by 5

x = 3

Now, substitute 3 for x in the equation.

y = \frac{2}{3}x- 4

y = \frac{2}{3}(3) - 4

y = 2 - 4

y = -2

The solution of the equation is x = 3, y = -2

4. Solving by elimination, let's try to eliminate the x-variable by adding both equation together.

3x - 2y = 11

-3x - y = 4

            -3y = 15  => (-3x +(-3x) = 0; -2y +(-y) = -3y; 11 + 4 = 15)

Divide both sides by -3 to solve for y

\frac{-3y}{-3} = \frac{15}{-3}

y = -5

Substitute -5 for y in the first equation to find x

3x - 2(-5) = 11

3x + 10 = 11

Subtract 10 from both sides

3x + 10 - 10 = 11 - 10

3x = 1

Divide both sides by 3

\frac{3x}{3} = \frac{1}{3}

x = \frac{1}{3}

The solution is x = \frac{1}{3}, y = -5

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3 years ago
What is the minimum whole number of passengers who need to get off the elevator to meet the weight requirement
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Do you know the weight requirement

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