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3 years ago

8

Como se dice en letras 600,00+80,000+10

2 answers:

garri49 [273]3 years ago

8 0

Seiscientos ochenta mill diez

Alinara [238K]3 years ago

4 0

<span>seiscientos ochenta mil y diez</span>

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NO LINKS!! NO MULTIPLE CHOICE!!

viva [34]

Answer:

Given points

A = (2, 1)
B = (4, 3)
C = (5, 3)
D = (6, 1)

<h3><u>Part (a)</u></h3>

See attached

<h3><u>Part (b)</u></h3>

Trapezoid

<h3><u>Part (c)</u></h3>

To dilate ABCD with a dilation center at (0,0) and a dilation factor of 4, multiply the x and y coordinates of ABCD by sf 4:

A' = (8, 4)
B' = (16, 12)
C' = (20, 12)
D' = (24, 4)

<h3><u>Part (d)</u></h3>

<u /> $\begin{aligned}\textsf{Area of Trapezoid}& =\dfrac{1}{2}(a+b)h\\\implies \textsf{Area of A'B'C'D'}& =\dfrac{1}{2}((x_{D'}-x_{A'})+(x_{C'}-x_{B'}))(y_{B'}-y_{A'})\\& = \dfrac{1}{2}((24-8)+(20-16))(12-4)\\& = \dfrac{1}{2}(20)(8)\\& = 80\: \sf units^2\end{aligned}$

5 0

2 years ago

Find the distance between the two points (-4, -5) and (1, -2).

Sphinxa [80]

Answer:

B

Step-by-step explanation:

Calculate the distance d using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 4, - 5) and (x₂, y₂ ) = (1, - 2)

d = $\sqrt{(1+4)^2+(-2+5)^2}$

= $\sqrt{5^2+3^2}$

= $\sqrt{25+9}$

= $\sqrt{34}$ → B

5 0

3 years ago

5.96 converted to a mix number?

nordsb [41]

U need to divide and then. Reduce

4 0

3 years ago

1.Shelly lives 500 miles away.Paul drove 65 mph for 4 hours.How many more miles will it take for him to arrive at Shelly’s house

Sladkaya [172]

1.240 miles
65*4=260
500-260

3 0

3 years ago

Find an equation of the plane with the given characteristics. The plane passes through the points (4, 3, 1) and (4, 1, -7) and i

Minchanka [31]

Answer:

$3x - 4y + z = 1$

Step-by-step explanation:

Given

$Point\ 1 = (4,3,1)$

$Point\ 2 = (4,1,-7)$

Perpendicular to $8x + 7y + 4z = 18$

Required

Determine the plane equation

The general equation of a plane is:

$a(x-x_1) + b(y - y_1) + c(z-z_1) = 0$

For $n =$

$(x_1,y_1,z_1) = (4,3,1)$

$(x_2,y_2,z_2) = (4,1,-7)$

First, we need to determine parallel vector $V_1$

$V_1 =$

$V_1 =$

$V_1 =$

$V_1$ is parallel to the required plane

From the question, the required plane is perpendicular to $8x + 7y + 4z = 18$

Next, we determine vector $V_2$

$V_2 =$

This implies that the required plane is parallel to $V_2$

Hence: $V_1$ and $V_2$ are parallel.

So, we can calculate the cross product $V_1 * V_2$

$V_1 =$

$V_2 =$

$n = V_1 * V_2$

$V_1 * V_2 =\left[\begin{array}{ccc}i&j&k\\0&2&8\\8&7&4\end{array}\right]$

The product is always of the form + - +

So:

$V_1 * V_2 = i\left[\begin{array}{cc}2&8\\7&4\end{array}\right]$ $-j\left[\begin{array}{cc}0&8\\8&4\end{array}\right]$ $+k\left[\begin{array}{cc}0&2\\8&7\end{array}\right]$

Calculate the product

$V_1 * V_2 = i(2*4- 8*7) - j(0*4- 8*8) + k(0*7 - 2 * 8)$

$V_1 * V_2 = i(8- 56) - j(0- 64) + k(0 - 16)$

$V_1 * V_2 = i(-48) - j(- 64) + k(- 16)$

$V_1 * V_2 = -48i +64j - 16k$

So, the resulting vector, n is:

$n =$

Recall that:

$n =$

By comparison:

$a = -48$ $b = 64$ $c = -16$

Substitute these values in $a(x-x_1) + b(y - y_1) + c(z-z_1) = 0$

$-48(x-x_1) + 64(y - y_1) -16(z-z_1) =0$

Recall that: $(x_1,y_1,z_1) = (4,3,1)$

So, we have:

$-48(x-4) + 64(y - 3) -16(z-1) =0$

$-48x + 192 + 64y -192 - 16z +16 = 0$

Collect Like Terms

$-48x + 64y - 16z = 0 - 192 + 192 - 16$

$-48x + 64y - 16z = -16$

Divide through by -16

$3x - 4y + z = 1$

<em>Hence, the equation of the plane is</em> $3x - 4y + z = 1$ <em></em>

4 0

3 years ago