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11Alexandr11 [23.1K]
3 years ago
10

How do I get this equation to equal 130 by putting parentheses in it...310-20÷2×5+13

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
8 0
The correct is 283 maybe
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In a café, I order a cup of tea and a piece of cake and it costs £1.10. The next time I order 2 cups of tea and one piece of cak
defon

Answer:

£0.50

Step-by-step explanation:

t = one cup of tea

c = one piece of cake

t + c = £1.10

2t + c = £1.70

the cost increases by £0.60 (£1.70 - £1.10) when you order one more cup of tea which means that one cup of tea costs £0.60

substitute £0.60 into t + c = £1.10

£0.60 + c = £1.10

rearrange to get c = £1.10 - £0.60 = £0.50

so one piece of cake costs £0.50

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3 years ago
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Describe the end behavior of the function.<br><br><br> f(x)=3(1/5)^x-2
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Answer:

The leading coefficient test requires a polynomial.

Not a polynomial

Step-by-step explanation:

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The following graph represents the cost and revenue functions for custom made computers. How many computers have been sold at th
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The answer is A) 12
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A survey was done that asked people to indicate whether they preferred pool swimming or ocean swimming. The results of the surve
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3 years ago
Find the expansion of cos x about the point x=0
ycow [4]

Answer:

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

Step-by-step explanation:

We use Taylor series expansion to answer this question.

We have to find the expansion of cos x at x = 0

f(x) = cos x, f'(x) = -sin x, f''(x) = -cos x, f'''(x) = sin x, f''''(x) = cos x

Now we evaluate them at x = 0.

f(0) = 1, f'(0) = 0, f''(0) = -1, f'''(0) = 0, f''''(0) = 1

Now, by Taylor series expansion we have

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)(x-a)^2}{2!} + \frac{f'''(a)(x-a)^3}{3!} + \frac{f''''(a)(x-a)^4}{4!} + ...

Putting a = 0 and all the values from above in the expansion, we get,

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

8 0
3 years ago
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