Find the area of each figure to the nearest tenth<br><br>I need helppp

AB is the perpendicular bisector of XY. Point P is the midpoint of XY. Which of the following are true?

Sonbull [250]

Hi - if you could provide a diagram, i could definitely help you!

8 0

3 years ago

Fred and his three friends go to the Ice Igloo for ice cream. Fred has $20 he earned mowing lawns and plans to pay for everythin

san4es73 [151]

I’m not sure but u need more information on your question

5 0

2 years ago

The bakers at Healthy Bakery can make 270 bagels in 10 hours. How many bagels can they bake in 15 hours? What was the rate per h

Tcecarenko [31]

Answer:

405 bagels 27 an hour

Step-by-step explanation:

this is because when you divide 270 by 10 you get 27 which is how much per hour then multiply the # of bagels and the # of hours you get is 405. In other words you first want to know how many bagels it took to get to 270 bagels in 10 hours.Hope it helped.

7 0

2 years ago

REALLY NEED HELP ASAP!!!!!!!

stich3 [128]

Answer: OPTION C

Step-by-step explanation:

There are some transformations for a function f(x). Some of them are shown below:

1. If $f(x)+k$ , the function is shifted up "k" units.

2. If $f(x)-k$ , the function is shifted down "k" units.

3. If $f(x+k)$ , the function is shifted left "k" units.

4. If $f(x-k)$ , the function is shifted right "k" units.

In this case you know that the function "g" is the transformation of the function "f".

Observe that the function "f" intersects the y-axis at:

$y=2$

And the function "g" intersects the y-axis at:

$y=-2$

Therefore, since both functions are 4 units apart, you can conclude that the function "f" was shifted down 4 units to get the function "g".

Then, the rule that shows that transformation is:

$g(x)=f(x)-4$

5 0

3 years ago

Experian would like to test the hypothesis that the average credit score for an adult in Virginia is different from the average

aliya0001 [1]

Answer:

a. We fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

b. The 95% confidence interval for the true difference of means is -2.2468 and 36.2468. There is a probability of 95% that the true difference of means $\mu_{1}-\mu_{2}$ is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

Step-by-step explanation:

Let $\mu_{1}-\mu_{2}$ be the true difference between the average credit score for an adult in Virginia and the average credit score for an adult in North Carolina. We have the large sample sizes $n_{1} = 40$ and $n_{2} = 35$ , the unbiased point estimate for $\mu_{1}-\mu_{2}$ is $\bar{x}_{1} - \bar{x}_{2}$ , i.e., 699-682 = 17.

The standard error is given by $\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$ , i.e.,

$\sqrt{\frac{(44)^{2}}{40}+\frac{(41)^{2}}{35}}$ = 9.8198.

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative). The rejection region is given by RR = {z | z < -1.96 or z > 1.96} where -1.96 and 1.96 are the 2.5th and 97.5th quantiles of the standard normal distribution respectively. The test statistic is $Z = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}}$ and the observed value is $z_{0} = \frac{17}{9.8198} = 1.7312$ . Because 1.7312 does not fall inside RR, we fail to reject the null hypothesis.

b. The endpoints for a 95% confidence interval for $\mu_{1}-\mu_{2}$ is given by $17\pm (z_{0.05/2})9.8198$ , i.e., $17\pm (z_{0.025})9.8198$ where $z_{0.025}$ is the 2.5th quantile of the standard normal distribution, i.e., -1.96, so, we have 17-(1.96)(9.8198) and 17+(1.96)(9.8198), i.e., -2.2468 and 36.2468. There is a probability of 95% that the true difference of means $\mu_{1}-\mu_{2}$ is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

3 0

3 years ago

Find the area of each figure to the nearest tenthI need helppp