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3 years ago

Solve for r V=2π/t•r

Mathematics

1 answer:

laila [671]3 years ago

5 0

$\dfrac{2\pi}{t}\cdot r=V\ \ \ \ |\cdot t\neq0\\\\2\pi r=Vt\ \ \ \ |:2\pi\\\\\boxed{Vt}{2\pi}}$

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Daniel [21]

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3 years ago

Which expression is equivalent to i 233?<br> a)1<br> b)–1<br> c)i<br> d)–i

Aneli [31]

We have to find the value of the expression $i^{233}$

We know that the below values.

$i^2=-1\\i^4=1$

Hence, in order to find the value of the given expression, we can first rewrite it in terms of $i^4$

$i^{233}=(i^4)^{58}\cdot i$

Now, we know that $i^4=1$

Hence, we have

$i^{233}=(1)^{58}\cdot i$

$i^{233}=1\cdot i$

$i^{233}=i$

C is the correct option.

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3 years ago

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How many pounds of cashew nuts worth 75 cents a pound must be mixed with 10 pounds of pecans worth $1.50 a pound to make a mixtu

Trava [24]

Let c represent the weight of cashews and p the weight of pecans.

Then c + 10 = total weight of the nut mixture.

An equation for the value of the mixture follows:

$1.50(10 lb) + $0.75c = (c+10)($1.00)

Solve this equation for c: 15 + .75c = c + 10. Subtract .75c from both sides:

15 = 1c - 0.75c + 10. Then 5=0.25c, and c = 5/0.25, or 20.

Need 20 lb of cashews.

Check: the pecans weigh 10 lb and are worth $1.50 per lb, so the total value of the pecans is $15. The total value of the cashews is (20 lb)($0.75/lb), or $15. Does (20 lb + 10 lb)($1/lb) = $15 + $15? Yes. So c= 20 lb is correct.

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riadik2000 [5.3K]

1/3 is equivalent to 33%

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grigory [225]

1 & 5/8 because 7/8 is closer to 1 whole than 5/8

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