What is the answer for 11,12,13,14,15 for analyzing lined ray segments and angles

Mathematics

1 answer:

MatroZZZ [7]3 years ago

4 0

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What is the answer to number nine also how do I solve for it? Thanks:)

Tanya [424]

Well the whole ratio is 14 sooooo
98 ÷ 14 =7

for food tents it would be 9 x 7 which is 63

And for retail tents 5 x 7which is 35

so the whole ratio is 63: 35

7 0

3 years ago

A certain car model has a mean gas mileage of 31 miles per gallon (mpg) with astandard deviation 3 mpg. A pizza delivery company

Effectus [21]

Answer:

Probability that the average mileage of the fleet is greater than 30.7 mpg is 0.7454.

Step-by-step explanation:

We are given that a certain car model has a mean gas mileage of 31 miles per gallon (mpg) with a standard deviation 3 mpg.

A pizza delivery company buys 43 of these cars.

Let $\bar X$ = sample average mileage of the fleet

The z-score probability distribution of sample average is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = mean gas mileage = 31 miles per gallon (mpg)

$\sigma$ = standard deviation = 3 mpg

n = sample of cars = 43

So, probability that the average mileage of the fleet is greater than 30.7 mpg is given by = P( $\bar X$  > 30.7 mpg)

P( $\bar X$ > 30.7 mpg) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{30.7 - 31}{\frac{3}{\sqrt{43} } }$ ) = P(Z > -0.66) = P(Z < 0.66)

= 0.7454

Because in z table area of P(Z > -x) is same as area of P(Z < x). Also, the above probability is calculated using z table by looking at value of x = 0.66 in the z table which have an area of 0.7454.

Therefore, probability that the average mileage of the fleet is greater than 30.7 mpg is 0.7454.

5 0

3 years ago

Find the value of x. Round your answer to the nearest tenth. 15 27

Lina20 [59]

Answer:

x ≈ 1318.2

Step-by-step explanation:

$tan(\frac{x}{15}) = 27$ Tangent = opposite over adjacent