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2 years ago

A plane intersects the prism parallel to the base. Which best describes the cross section? (5 points)

Mathematics

1 answer:

Crazy boy [7]2 years ago

4 0

Answer:

The Reconstruction Amendments are the Thirteenth, Fourteenth, and Fifteenth amendments to the United States Constitution, adopted between 1865 and 1870, the five years immediately following the Civil War. The last time the Constitution had been amended was with the Twelfth Amendment more than 60 years earlier in 1804.

Step-by-step explanation:

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Based on the results from part C, which two statements correctly interpret actions the business should take? If material 2 is us

Serjik [45]

The profit function is the difference between the cost and the revenue functions.

The true statement is (a) If material 2 is used, Carrie will earn a profit if she sells chairs for more than $150 each.

<h3>How to determine the true profit functions</h3>

From the complete questions, the profit functions are calculated as follows:

Material 1

$P(x) = 5000000- 20000x - 200000x + 2000x^2$

$P(x) = 5000000-220000x + 2000x^2$

Material 2

$P(x) = 4000000 - 10000x - 160000x+ 1000x^2$

$P(x) = 4000000-170000x+ 1000x^2$

Material 3

$P(x) = 2000000 - 5000x - 54000x - 270x^2$

$P(x) = 2000000 -59000x - 270x^2$

Next, we test the options

Option 1: When material 2 is used

A price is greater than $150 is $151.

Calculate P(151) using $P(x) = 4000000-170000x+ 1000x^2$

So, we have:

$P(151) = 4000000-170000 * 151+ 1000* 151^2$

$P(151) = 1131000$

P(151) is greater than 0; this represents a profit

Hence, option (1) is true

Option 2: When material 1 is used

A price is less than $50 is $49.

Calculate P(49) using $P(x) = 5000000-220000x + 2000x^2$

So, we have:

$P(49) = 5000000-220000 * 49 + 2000* 49^2$

$P(49) =-978000$

P(49) is less than 0; this represents loss

Hence, option (2) is false

Option 3: When material 3 is used

Calculate P(45) and P(160) using $P(x) = 2000000 -59000x - 270x^2$

So, we have:

$P(45) = 2000000 -59000 * 45 - 270 * 45^2$

$P(45) = -1201750$

P(45) is less than 0; this represents loss

Hence, option (3) is false

Option 1: When material 2 is used

Calculate P(30) and P(120) using $P(x) = 4000000-170000x+ 1000x^2$

So, we have:

$P(30) = 4000000-170000*30+ 1000*30^2$

$P(30) = -200000$

P(30) is less than 0; this represents a loss

Hence, option (4) is false

Option 2: When material 1 is used

Calculate P(40) and P(70) using $P(x) = 5000000-220000x + 2000x^2$

So, we have:

$P(40) = 5000000-220000*40 + 2000*40^2$

$P(40) = -600000$

P(49) is less than 0; this represents loss

Hence, option (5) is false

The above means that:

The true statement is (a) If material 2 is used, Carrie will earn a profit if she sells chairs for more than $150 each.

Read more about revenue functions at:

brainly.com/question/25638609

6 0

2 years ago

4. Find the shortest length that can be cut into exact equal lengths of 4cm or 18cm (3mks)

garik1379 [7]

Answer:

4 cm

Step-by-step explanation:

6 0

2 years ago

PLEASE HELP QUICKLY 25 POINTS

Natalija [7]

Answer:

○ $\displaystyle \pi$

Step-by-step explanation:

$\displaystyle \boxed{y = 3sin\:(2x + \frac{\pi}{2})} \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{4}} \hookrightarrow \frac{-\frac{\pi}{2}}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 3$

OR

$\displaystyle \boxed{y = 3cos\:2x} \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 3$

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of $\displaystyle y = 3sin\:2x,$ in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted $\displaystyle \frac{\pi}{4}\:unit$ to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD $\displaystyle \frac{\pi}{4}\:unit,$ which means the C-term will be negative, and by perfourming your calculations, you will arrive at $\displaystyle \boxed{-\frac{\pi}{4}} = \frac{-\frac{\pi}{2}}{2}.$ So, the sine graph of the cosine graph, accourding to the horisontal shift, is $\displaystyle y = 3sin\:(2x + \frac{\pi}{2}).$ Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit $\displaystyle [-1\frac{3}{4}\pi, 0],$ from there to $\displaystyle [-\frac{3}{4}\pi, 0],$ they are obviously $\displaystyle \pi\:units$ apart, telling you that the period of the graph is $\displaystyle \pi.$ Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at $\displaystyle y = 0,$ in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.