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4 years ago

6.5x=42.25 what is the answer to this eqesion?

Mathematics

1 answer:

Aloiza [94]4 years ago

4 0

42.25 / 6.5 = x = 6.5

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What is the domain of log5x?

Rus_ich [418]

The answer is both a and b, but I think you meant to switch the greater/less signs, so then it would be x > 0.

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3 years ago

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Harman [31]

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3 years ago

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the stan

Crank

Answer:

Step-by-step explanation:

We are given coordinates of the line passed through (–5, –1) and (10, –7) .

Applying slope formula,

$Slope=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-5,\:-1\right),\:\left(x_2,\:y_2\right)=\left(10,\:-7\right)$

Therefore,

$m=\frac{-7-\left(-1\right)}{10-\left(-5\right)}$

$m=-\frac{2}{5}$

Therefore, slope is $m=-\frac{2}{5}$ .

Applying point-slope form $y-y_1=m(x-x_1),$ we get

$y+7 = -\frac{2}{5}(x-10)$

$y+7=-\frac{2}{5}(x-10)$

On multiplying both sides by 5, we get

$5(y+7)=5\times-\frac{2}{5}(x+1)$

5y+35=-2(x-10)

5y+35=-2x+20

Adding 2x on both sides, we get

5y+25+2x=-2x+20+2x

2x+5y+35=20

Subtracting 35 from both sides, we get

2x+5y+35-35=20-35

2x+5y=-15.

Therefore, required equation is :

6 0

3 years ago

A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The prem

scoundrel [369]

Answer:

let w = amt of water required

An equation based on the the percent water, an 80% solution is 20% water.

.20(320-w) + w = .50(320)

64 - .2w + w = 160

.8w = 160 - 64

w = 96%2F.8

w = 120 gal of water to produce 320 gal of 50% antifreeze

320 - 120 = 200 gal of 80% solution

Water: _120___ gallons

Premium Antifreeze: __200___ gallons

Step-by-step explanation:

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3 years ago

What is the slope of the line passing through -7,-2 and 4,1

Vladimir [108]

The slope is for that would be 3/11

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3 years ago