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vazorg [7]
2 years ago
8

What is the volume of a football in cm³​

Mathematics
1 answer:
Yuki888 [10]2 years ago
6 0

Answer:

Around 4800 cubic centimeters.

I hope this was helpful.

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Please help with this question.
Kisachek [45]
The answer is the top option.
5 0
3 years ago
Suppose you draw a card from a well shuffled deck of playing cards what is probability of drawing a ace
Tasya [4]
So there are a totally of 52 cards right?(not counting jokers because jokers are not in official cards)
And there are 4 aces right?
So there are 52 outcomes and 4 of them are aces.
So when we write probabilities we write it in fraction form where the total number of outcomes is the denominator and the ones you want to get are the numerator OK?
So the total number is outcomes is 52 and becomes the denominator and 4 the number of aces become the numerator.
So 4/52 right?
And we now have to simplify it right?
And so we divide by the highest common factor right?
In this case 4 because there isn’t other numbers that are factors and greater than 4.
So 4 divided by 4/52 is 1/13 right?
4 goes into 4 1 time and 13 times into 52.
So your answer is 1/13
3 0
3 years ago
Find the missing length indicated.<br> X=
goblinko [34]

Answer:

128

Step-by-step explanation:

64*2= 128

Your answer should be 128.

I hope you understand my horrible explnation.

5 0
3 years ago
Dion is out shopping and finds a basketball jersey originally valued at $128.00. it is now on sale for 75% of the original price
Fittoniya [83]

Answer:

$96

Step-by-step explanation:

$128 X 78/100

= $128 X .75

= $96

Dion would buy it, he's rich

7 0
2 years ago
Find the quotient of these Complex Numbers. <br><br><br> (5-i) / (3+2i)
JulsSmile [24]

Let the given complex number

z = x + ix = \dfrac{5-i}{3+2i}

We have to find the standard form of complex number.

Solution:

∴ x + iy = \dfrac{5-i}{3+2i}

Rationalising numerator part of complex number, we get

x + iy = \dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}

⇒ x + iy = \dfrac{(5-i)(3-2i)}{3^2-(2i)^2}

Using the algebraic identity:

(a + b)(a - b) = a^{2} - b^{2}

⇒ x + iy = \dfrac{15-10i-3i+2i^2}{9-4i^2}

⇒ x + iy = \dfrac{15-13i+2(-1)}{9-4(-1)} [ ∵ i^{2} =-1]

⇒ x + iy = \dfrac{15-2-13i}{9+4}

⇒ x + iy = \dfrac{13-13i}{13}

⇒ x + iy = \dfrac{13(1-i)}{13}

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0
3 years ago
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