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3 years ago

PLS HELP 15 POINTS! Find part “b”.

Mathematics

1 answer:

Ilya [14]3 years ago

7 0

Answer:

b=45/4

Step-by-step explanation:

This is a special triangle 30-60-90.

In big triangle hypotenuse 15, short leg x=(hypotenuse/2), x=15/2.

In smallest triangle :

1. This is also special triangle 30-60-90

2. x=15/2 hypotenuse

3. "a" is a shortest leg in the smallest triangle,

so a=(15/2)/2=15/4

a+b=15

15/4 +b=15

b=15 -15/4=15*4/4 -15/4 = 45/4

b=45/4

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3 years ago

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What is the answer of 81g^2 - 36f^2 ?????

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2 years ago

You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b

Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

$\mathbf{x = 100\ m}$

$\mathbf{\frac{dy}{dt} = 2\ ms^{-1}}$ ---- the rate

$\mathbf{\theta = \frac{\pi}{4}}$

First, we calculate the vertical distance (y) using tangent ratio

$\mathbf{\tan(\theta) = \frac{y}{x}}$

Substitute 100 for x

$\mathbf{y = 100\tan(\theta) }$

$\mathbf{\tan(\theta) = \frac{y}{100}}$

Differentiate both sides with respect to time (t)

$\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}$

Substitute values for the rates and $\mathbf{\theta }$

$\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

This gives

$\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

$\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

Divide both sides by 2

$\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }$

$\mathbf{ \frac{d\theta}{dt} = 0.01 }$

Hence, the rate of change between you and the ball is 0.01 rad per second

Read more about related rates at:

brainly.com/question/16981791

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2 years ago

A company is bidding on two projects, A and B. The probability that the company wins project A is 0.40 and the probability that

kondaur [170]

Answer:

Probability that the company wins project A or project B is 0.50.

Step-by-step explanation:

We are given that a company is bidding on two projects, A and B. The probability that the company wins project A is 0.40 and the probability that the company wins project B is 0.25.

Also, Winning project A and winning project B are independent events.

Let the Probability of winning project A = P(A) = 0.40

Probability of winning project B = P(B) = 0.25

Now, as we know that ;

Probability that the company wins project A or project B = $P(A \bigcup B)$

$P(A \bigcup B) = P(A) + P(B) - P(A \bigcap B)$

So, we have to find the value of Probability of winning project A and B, i.e;

$P(A \bigcap B)$

Since, we are given that Winning project A and winning project B are independent events which means when this condition is given then;

$P(A \bigcap B) = P(A) \times P(B)$

= 0.40 $\times$ 0.25 = 0.10

Now, Probability that the company wins project A or project B is given by;

$P(A \bigcup B) = P(A) + P(B) - P(A \bigcap B)$

= 0.40 + 0.25 - 0.10

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Hence, probability that the company wins project A or project B is 0.50.

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3 years ago