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Alina [70]
4 years ago
9

Find slope x-intercept=5,y-intercept=3

Mathematics
1 answer:
shutvik [7]4 years ago
7 0
Intercepts<span> occur when a line crosses the </span>x<span>-axis or the </span>y<span>-axis. When the line crosses the </span>x<span>-axis, then </span>y<span> = 0 and </span>x<span> = </span>3<span>. ... The </span>intercept<span> points are (0, 4) and (</span>3<span>, 0 ). So the </span>y-intercept<span> is 4 and the </span>x intercept<span> is </span>3<span> and the sum is 7.</span>
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a scientist began a study with a simple of 1,500 bacteria . he noticed that the number of bacteria in the simple after t days ca
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Answer:

the variable

Step-by-step explanation:

7 0
3 years ago
2s+10-7s-8+3s-7<br> syplifying expression fyi​
Solnce55 [7]

Answer:

-1+5z, -25+20y, 4d+14, 2n-2, 40k+8, 8b+5, -9+22p

Step-by-step explanation:

1) -4+7z+3-2z

-1+5z

2) 15+4(5y-10)

15+20y-40

-25+20y

3) 2d+17-3-2d+4d

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8b+5

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7 0
3 years ago
"without performing an inverse laplace transform, find the limiting value"
maks197457 [2]
If your transformed function is F(s), the limiting value of f(t) as t goes to infinity is the limiting value of s*F(s) as s goes to zero.

Multiply your function by s, then evaluate for s=0. If the form is indeterminate, evaluate the limit as s approaches zero.
8 0
3 years ago
Find the center and the radius of the circle with the equation: x2-4x+y2-12y+31=0
Gelneren [198K]

Answer:

centre = (2, 6) and radius = 3

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

To obtain this form complete the square on both the x and y terms

express the equation as

x² - 4x + y² - 12y = - 31

x² + 2(- 2)x + 4 + y² + 2(- 6)y + 36 = - 31 + 4 + 36

(x - 2)² + (y - 6)² = 9 ← in standard form

with centre = (2, 6) and r = \sqrt{9} = 3


4 0
3 years ago
Read 2 more answers
Please help solve this and show work
dlinn [17]
Subtract 43 from both sides of equation

3 0
3 years ago
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