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3 years ago

Approximate √39 to the nearest whole number

Mathematics

1 answer:

vladimir2022 [97]3 years ago

4 0

36 < 39 < 49

√36 < √39 < √49

6 < √39 < 7

√39 ≈ 6

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Priya's cat is pregnant with a litter of 5 kittens. Each kitten had a 30% chance of being chocolate brown. Estimate the probabil

aniked [119]

Answer:

So, the probability is P=0.3087.

Step-by-step explanation:

We know that Priya's cat is pregnant with a litter of 5 kittens, so n=5.

Each kitten had a 30% chance of being chocolate brown.

We get that p=0.3 and q=1-0.3=0.7.

We calculate the probability that exactly 2 kittens will be chocolate brown, so k=2.

We use the formula:

$\boxed{P(X=k)=C_k^n\cdot p^k\cdot q^{n-k}}$

we get

$P(X=2)=C_2^5\cdot 0.3^2\cdot 0.7^3\\\\P(X=2)=\frac{5!}{2!(5-2)!}\cdot 0.03087\\\\P(X=2)=10\cdot 0.03087\\\\P(X=2)=0.3087\\$

So, the probability is P=0.3087.

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4 years ago

PLEASE HURRY! WILL GIVE 5 STARS! AND THANKS!

solong [7]

Answer:

7/24

Step-by-step explanation:

2/3 - 3/8

2/3 + -3 / 8

16 / 24 + -9 / 24

16 + -9 / 24 = 7/24 (already simplest form, decimal form is 0.291667)

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4 years ago

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lisov135 [29]

Step-by-step explanation:

Its the bottom question sir

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3 years ago

Translate the following sentence in Spanish<br> They have no interest in cleaning the bathroom.

Aleonysh [2.5K]

Answer:

No tienen ningún interés en limpiar el baño.

Step-by-step explanation:

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3 years ago

USA Today surveyed fifty-five working parents and asked them if they feel they spend too little time with their children due to

Bezzdna [24]

Answer:

d. (0.5457 , 0.8361)

Step-by-step explanation:

From the missing findings recorded in the Excel output; we have:

the sample size to be = 55

count of response = 38

So, the proportion of parents that have the feeling they do spend little time with their children are :

p = $\dfrac{38}{55}$

p= 0.69

Thus, p = sample mean $\overline x$ = 0.69

The standard error of the proportion p is expressed as:

$S.E = \sqrt{\dfrac{p (1-p)}{n}}$

$S.E = \sqrt{\dfrac{0.69 (1-0.69)}{55}}$

$S.E = \sqrt{\dfrac{0.69 (0.31)}{55}}$

$S.E = \sqrt{\dfrac{0.2139}{55}}$

$S.E = \sqrt{0.003889}$

S.E = 0.06236

At 98% confidence interval level, the level of significance = 1 - 0.98 = 0.02

$z_{0.02/2} =2.326$

Confidence interval = $p \pm z_{0.02/2} \times S.E$

Confidence interval = $0.69 \pm 2.326 \times 0.062$

Confidence interval = $0.69 \pm 0.144212$

Confidence interval = $(0.69 - 0.144212 \ , \ 0.69 +0.144212 )$

Confidence interval = $(0.545788 \ , \ 0.834212 )$

Thus, option d. (0.5457 , 0.8361) is the right answer

4 0

3 years ago