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Darina [25.2K]
3 years ago
13

Solve please This is Composite Figures :)

Mathematics
1 answer:
Ksivusya [100]3 years ago
7 0
The area is that of two 20 yd squares and one 20 yd circle.
.. A = 2*(20 yd)^2 +(π/4)*(20 yd)^2
.. = (2 +π/4)*(400 yd^2)
.. = (800 +100π) yd^2
.. ≈ 1114.16 yd^2

The perimeter is that of a 20 yd circle and 80 yd more.
.. P = π*20 yd + 80 yd
.. ≈ 142.83 yd
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What is the vertical asymptote of this function?
liraira [26]

Answer:

D

Step-by-step explanation:

If y = log x is the basic function, let's see the transformation rule(s):

Then,

1. y = log (x-a) is the original shifted a units to the right.

2. y = log x + b is the original shifted b units up

Hence, from the equation, we can say that this graph is:

** 2 units shifted right (with respect to original), and

** 10 units shifted up (with respect to original)

<u><em>only, left or right shift affects vertical asymptotes.</em></u>

Since, the graph of y = log x has x = 0 as the vertical asymptote and the transformed graph is shifted 2 units right (to x = 2), x = 2 is the new vertical asymptote.

Answer choice D is right.

7 0
3 years ago
Divide the following polynomials using the long division model (4x ^ 4 - 5x ^ 3 + 2x ^ 2 - x + 5) + (x ^ 2 + x + 1)
densk [106]

Answer:

The ramainder is equal -86

Step-by-step explanation:

Since the polynomial degree Q(x) is 1, the remainder of the division must be a number. Therefore we only need to calculate the value of polynomial for x = -2

5 0
3 years ago
Does (0,0) satisfy x+3y&gt;3
PtichkaEL [24]

\bf x+3y > 3\qquad \qquad (\stackrel{x}{0}~~,~~\stackrel{y}{0})\qquad \qquad 0+3(0) > 3\implies \stackrel{\stackrel{\textit{is this true?}}{\downarrow }}{0>3}\qquad nope!

4 0
3 years ago
Five times the same of a number.
Tanzania [10]

5 ( x + 3) = 6x - 3

5x + 15 = 6x - 3

x = 18 <====== this is the number

6 0
3 years ago
A ball is thrown from an initial height of 2 feet with an initial upward velocity of 29 ft/s. The balls height (h) [in feet] aft
nirvana33 [79]
The ball is at a height of 14 feet after 1.17 and 0.64 seconds.

This is an example of a quadratic equation. Write out the equation with 14 in the place of the height. Then, set it equal to zero.

14 = 2 + 29t - 16t^2

0 = -16t^2 + 29t -12

Now, we can use the quadratic equation to solve.
A = -16
B = 29
C = -12

You will get the solutions of 1.17 and 0.64.
5 0
3 years ago
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