All categories

3 years ago

Help please.................

Mathematics

1 answer:

olganol [36]3 years ago

6 0

Answer:

(-4, 0) and (5/2, 0)

Step-by-step explanation:

if you graph the equation you can see where the curve intersects the x-axis or you can factor the equation into: (2x - 5)(x + 4) = 0

set each factor equal to zero and solve:

2x - 5 = 0

2x = 5

x = 5/2

x + 4 = 0

x = -4

You might be interested in

The Orchard Cafe has found that about 3% of the diners who make reservations don't show up. If 83 reservations have been made, h

daser333 [38]

Answer:

$\mu = 80.51\\\sigma = 1.56$

Step-by-step explanation:

We are given the following information in the question:

Percentage of of the diners who make reservations don't show up = 3%

Number of reservations = 83

Thus, we are given a binomial distribution with n = 83 and p = 0.97

$X\sim \text{ Binom}(p = 0.97, n = 83)$

$\mu = np = (83)(0.97) = 80.51$

Around 81 people can be expected to show up.

$\sigma = \sqrt{np(1-p)} = \sqrt{(83)(0.97)(1-0.97)} = 1.5541 \approx 1.56$

The standard deviation of this distribution is 1.56

6 0

3 years ago

Let f(x)=x^2+5x−8. What is the average rate of change from x = 2 to x = 6?

Lena [83]

F(2)=4+10-8=6; f(6)=36+30-8=58. Average rate of change is (58-6)/(6-2)=52/4=13

7 0

4 years ago

Consider the following table does this represent a function why or why not?

NARA [144]

This doesn't represent an function. Because the output is uneven to the other outputs,
1=4, 2=7 if you divided 2 into 2 parts it would equal 1=3.5 not 4.

8 0

3 years ago

Write the exponential equation for this scenario. Mike buys a car for $45,000.00. The cars value depreciates (loses value) at a

gladu [14]

Answer:

$A=45000(0.82)^t$

Step-by-step explanation:

Given data

P= 45,000

rate= 18%

Recall the expression for the compound interest

$A=P(1+r)^t$

Since we are talking of depreciation

$A=P(1-r)^t$

Substitute

$A=45000(1-0.18)^t\\\\A=45000(0.82)^t$

Hence the exponential function is

$A=45000(0.82)^t$

6 0

3 years ago

A radioactive substance has a continuous decay rate of 0.056 per minute. How many grams of a 120 gram sample will remain radioac

sammy [17]

Answer:

The mass of the radioactive sample after 40 minutes is 12.8 g.

Step-by-step explanation:

The mass of the sample can be found by using the exponential decay equation:

$N_{t} = N_{0}e^{-\lambda t}$

Where:

N(t): is the amount of the sample at time t =?

N₀: is the initial quantity of the sample = 120 g

t = 40 min

λ: is the decay constant = 0.056 min⁻¹

Hence, the mass of the sample after 40 min is:

$N_{t} = N_{0}e^{-\lambda t} = 120g*e^{-0.056min^{-1}*40 min} = 12.8 g$

Therefore, the mass of the radioactive sample after 40 minutes is 12.8 g.

I hope it helps you!

5 0

3 years ago