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spin [16.1K]
3 years ago
7

Solve the following system by the comparison method.

Mathematics
1 answer:
agasfer [191]3 years ago
5 0

Answer:

2p + q = 1

9p + 3q + 3 = 0

q = 1 - 2p

replace q = 1 - 2p into 9p + 3q + 3 = 0

9p + 3(1 - 2p) + 3 = 0

9p + 3 - 6p + 3 = 0

3p + 6 =0

3p = -6

p = -2

q = 1 - 2p

q = 1 -2(-2)

q = 1 + 4

q = 5

(-2 , 5)

there for the answer would be

{(-2, 5)}

Hopefully this was helpful <3 :3

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What is the surface area of a square pyramid that has a base length of 5 inches and triangular faces that are 9 inches tall
scZoUnD [109]

Answer:

115 in²

Step-by-step explanation:

SA = Area of triangular surfaces + area of the square base

SA= 2bh + b²

SA = 2(5)(9)+5²

SA = 90+25

SA = 115

7 0
3 years ago
COMPLETE THE FOLLOWING EQUATION USING APPROPRIATE SIGN ( +,-,x,÷) IN THE BOXES GIVEN:
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Answer:

) +, -

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Step-by-step explanation:

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2 years ago
Solve.
Nikitich [7]
The answer is C: 10\text{ }^1/_2. Here are the details:

\text{Equation:}\\ 6\text{ }^1/_3+10\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 6+10=16\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^1/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^2/_6+\text{ }^3/_6=\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Add 'em up!}\\&#10;16\text{ }^5/_6

\text{Equation:}\\&#10;16\text{ }^5/_6+3\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Start with the integers.}\\&#10;16+3=19\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{...then with the fractions, but rewrite them first to make it easier.}\\&#10;^5/_6+\text{ }^5/_6=\text{ }^{10}/_6\stackrel{\text{rewrite}}{\to}\text{ }^5/_3\stackrel{\text{rewrite}}{\to}1\text{ }^2/_3\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Add 'em up!}\\&#10;20\text{ }^2/_3

\text{Last equation:}\\ 20\text{ }^2/_3+5\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 20+5=25\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^2/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^4/_6+\text{ }^3/_6=\text{ }^7/_6\stackrel{\text{rewrite}}{\to}1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Add the integer and fraction together.}\\&#10;25+1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6

26\text{ }^1/_6\stackrel{\checkmark}{=}26\text{ }^1/_6
5 0
3 years ago
-(1+7x)-6(-7-x)=36 what is x equal to
Katyanochek1 [597]

Answer:

x = 5

Step-by-step explanation:

Step 1: Write equation

-(1 + 7x) - 6(-7 - x) = 36

Step 2: Solve for <em>x</em>

  1. Distribute: -1 - 7x + 42 + 6x = 36
  2. Combine like terms: -x + 41 = 36
  3. Subtract 41 on both sides: -x = -5
  4. Divide both sides: x = 5

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

-(1 + 7(5)) - 6(-7 - 5) = 36

-(1 + 35) - 6(-12) = 36

-(36) + 72 = 36

-36 + 72 = 36

36 = 36

5 0
4 years ago
Which square root is between 4 and 5
shusha [124]
Answer:
I’m not sure what you mean by divided, but the square root of 24 would be between 4 and 5.

Explanation:
I translated 4 and 5 into square roots, being the square root of 16 (4^2) and the square root of 25 (5^2).
4 is equal to the square root of 16 just as 5 is equal to the square root of 25.
Of the given square roots in the answers, only the square root of 24 was between the square roots of 16 and 25. Therefore, the square root of 24 is between 4 and 5.
8 0
3 years ago
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