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2 years ago

Do the following lengths form a right triangle?

Mathematics

1 answer:

Dmitry_Shevchenko [17]2 years ago

5 0

Answer:

yes, this forms a right angle

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If f(x) 3 x-1+ 4 and g(x) 4x-7 what is (f-g)(x)?

andre [41]

Hello :
If f(x)= 3 ^x-1+ 4 and g(x) = 4x-7
(f-g)(x) = f(x) - g(x)= 3 ^x-1+ 4 - (4x - 7)
(f-g)(x) =3 ^x-1-4x +11.....( answer : a)

5 0

3 years ago

Read 2 more answers

A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient

ankoles [38]

Answer:

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

Solution:

We need to show that the gradient of the curve at A is 1

Here given that ,

$y=(x-a) \sqrt{(x-b)}$ --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

$y^{\prime}=u^{\prime} y+y^{\prime} u$

so, we get

${u}^{\prime}=1$

$v^{\prime}=\frac{1}{2} \sqrt{(x-b)}$

$y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}$

By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

$y^{\prime}=\frac{d y}{d x}=1$

Hence proved that the gradient of the curve at A is 1.

7 0

2 years ago

Use synthetic division to find the quotient of (44 + 22 − 4 + 12) ÷ ( + 2). Show your work for full credit.

valina [46]

Just remember BODMAS, which B= brackets O= Order D= Division M= Multiply A=Addition and S=Subtract

So first you solve the brackets so 44+22 is 66

So 66-4+12 so 66-4 is 62

62+12 is 74

So now you have got 74 divided by 2 which is 37

Hope this helps xx

5 0

3 years ago

The elevation of Sports Authority Field in Denver, Colorado is 5280ft. If this is 275ft higher than seven times the elevation of

kap26 [50]

Answer:

The elevation of Lucas Oil Field is of 715 feet.

Step-by-step explanation:

Elevation of Sports Authority Field:

Of 5280 ft.

Compared to Lucas Oil Field:

275ft than seven times the Lucas Oil Field elevation of x.

Equation: