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Serhud [2]
3 years ago
14

A mountain climber starts a climb at an elevation of 453 feet above sea level. At his first rest stop he has climbed 162 feet, a

nd by his second rest stop he has climbed another 207 feet. It's getting late in the day, so the climber starts his way down. If the climber descends 285 feet, how much does he need to ascend or descend to return to the original starting point? A) ascend 84 feet B) ascend 78 feet C) descend 84 feet D) descend 78 feet
Mathematics
1 answer:
Alenkinab [10]3 years ago
7 0

They started at 453, then climbed 162, so now they are at:

453 + 162 = 615 feet.

They then cllmb another 207 feet to get to:

615 + 207 = 822 feet.

They then descend ( climb down) 285 feet.

822 - 285 = 537 feet.

Now they need to get back tot he original 453,

so they have to descend:

537 - 453 = 84 more feet.

The answer is C.

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Leah is writing an equivalent equation which solves for y. What should be her next step? 3x+4y=8 Add 4y to both sides of the equ
ratelena [41]

The given equation is

3x+4y=8

And we have to solve for y.

Solving for y, means isolating y . And to isolate y, we need to get rid of 4 that is with y .

It means we have to separate 4 from y, and for separation , we have to perform division. That is, we have to divide both sides by 4, and that will be the next step .

So out of the four options, correct option is the last option .

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The rectangular coordinates of a point are given. Find the polar coordinates ​(r,theta​) of this point with theta expressed in r
alexandr402 [8]

Answer:}

In polar coordinates P is

P  ( 12 ; 2.618 )  

Step-by-step explanation:

The point (ectangular coordinates)  

P ( -6√3  ;   6 )       P  (  x ; y )

Polar coordinates   P ( r  ;  θ )

x = r cos θ

y = r sin θ                  r > 0    and     0  ≤ θ ≤ 2π

Then

r  =  √ (x)² + (y)²        r  =  √(36)²*3 +( 36)²       r = √144

r  =  12   (hypothenuse module always positive)

The point   P  ( -6√3  ;   6 )   is in second cuadrant  between 90° and 180°

angle between  r  and horizontal axis x  is equal to θ

tan α =  l.opp/ l.adj.    tan θ =  y/x       tan θ = - 6 /6√3

tan α = - 1/√3

Then α  =  180⁰ - 150⁰  = 30⁰  or     θ =  150⁰

to express that value in radians we have :

1 π radian      =   180⁰         ⇒   3,1416   radians  =  180⁰

                                                      x ??                  =   150⁰

x =  radians

Finally the point is   P  ( 12 ; 2.618 )  

6 0
3 years ago
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