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Ainat [17]
3 years ago
12

I'm trying to find out if the system have a unique solution, no solution or infinitely many solutions

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
7 0
Both have no solution
kow [346]3 years ago
6 0
Alright so this is what you do.
You need to isolate one variable so that it is y = or x =
Lets go with y = for the first one

-x +3y = -6
x - 3y = 6

Isolate y = by adding x for the first one and then subtracting x from the second one.
3y = -6 + x
-3y = 6 - x

You would then divide the second one by -3 and divide by 3 in the first one.

y = (-6 +x) / 3
y = (6 -x) / -3
Since this is what y = you can put them together.

-6+x) / 3 = 6-x)/-3 (I put one parenthesis for convenience)

This equation is now set and you aren't done yet.
You can take out -1 from each side. This makes it no solution since you must always multiply by -1.
(6+x) / 3 = -1( (6+x) / 3)

Try the second one on your own!
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An event that has probability 1 <br>is said to be<br>​
mafiozo [28]

Answer:

guaranteed to occur

Step-by-step explanation:

An event that has a probability of 1 or in other terms P(E) = 1 is said to be guaranteed to occur. This is basically stating that the event has a 100% chance of happening, meaning that no matter what the external factors turn out to be in the scenario, the event will occur regardless. 1 basically represents 100%, while lower values such as 0.5 represent 50% when dealing with these probabilities.

7 0
3 years ago
the cost of a candle varies directly with the volume of a candle. if a candle with a volume of 80cm^3 costs $12, what would be t
a_sh-v [17]

120 \div 8. = 1.5

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the answer is $18


good luck
7 0
3 years ago
1. The midpoint of the segment joining points (a, b) and ( j, k) is: a. (j-a,k-b) b. ((j-a)/2,(k-b)/2) c. (j+a,k+b) d. ((j+a)/2,
harkovskaia [24]
1. The midpoint of the segment joining points (a, b) and ( j, k) is ((j+a)/2,(k+b)/2)

2. Let the coordinate of H be (a, b)
T(0, 4) = ((a + 0)/2, (b + 2)/2)
(a + 0)/2 = 0 => a + 0 = 0 => a = 0
(b + 2)/2 = 4 => b + 2 = (2 x 4) = 8 => b = 8 - 2 = 6
Therefore, the cordinate of H is (0, 6)

3. Point (-4, 3) lies in Quadrant II

4. Point (6, 0) lies on the x-axis

5. Any line with no slope is parallel to the y-axis

7. a is the value of the x-coordinate.
5a + 3 = 8
5a = 8 - 3 = 5
a = 5/5 = 1
a = 1

8. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => a = -5 and b = 7.
Therefore, its center point is (-5, 7)

9. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => r = 6.
Therefore, its radius is 6

10. If the equation of a circle is (x - 2)^2 + (y - 6)^2 = 4, the center is point (2, 6).
True

7 0
3 years ago
Read 2 more answers
23j-21g+20e-13+52e-37j+45-49e<br> (Like terms)
eduard

The solution to the algebraic expression is: 23e - 21g - 14j + 32

What are algebraic expressions?

Algebraic expressions are mathematical expressions that contain variables, coefficients, and arithmetic operations such as addition, subtraction, division, and multiplication.

Solving algebraic expressions are an important part of mathematics as it helps to improve the aptitude and solving skills of the students.

From the given information, we have;

23j - 21g + 20e - 13 + 52e - 37j + 45 - 49e

let's rearrange by taking the like terms to the same sides;

= 23j -37j - 21g + 20e + 52e - 49e - 13 + 45

= -14j - 21g + 23e + 32

= 23e - 21g - 14j + 32

Therefore, we can conclude that the solution to the algebraic expression is: 23e - 21g - 14j + 32

Learn more about solving algebraic expressions here:

brainly.com/question/4344214

#SPJ1

3 0
2 years ago
You buy a book of 5 basketball tickets for $62.50. What is the rate of cost per ticket?
Kisachek [45]
12.50 as 12.50 x 5 is 62.50 or as we know 62.50 for 5 we do 62.50/5 to get 12.50
4 0
3 years ago
Read 2 more answers
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