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bogdanovich [222]
3 years ago
12

PLEASE help Asap please

Mathematics
1 answer:
puteri [66]3 years ago
8 0
I believe the answer would be 5 pages.
If you would like to see my work please reply saying so.
Hope this could help.
You might be interested in
A room has an area of 60 square meters and a perimeter of 32 meters. What are the length and width of the room?
Dominik [7]

Answer:

6 and 10

Step-by-step explanation:

xy=60

2(x+y)=32

x+y=16

y=16-x

Substitute y into area equation

x(16-x)=60

16x-x^2=60

x^2-16x+60=0

(x-10)(x-6)=0

x=10, 6

y=6, 10

6 0
2 years ago
3-5b=3-b-4b <br> no solution, one solution,<br> infinitely many solutions
Leni [432]
Infinity many solutions because they both equal the same when the problem is solved.
3 0
3 years ago
What is the y-intercept of the line perpendicular to the line y = four thirdsx + 1 that includes the point (4, 1)?
s2008m [1.1K]

Answer:

(C)4

Step-by-step explanation:

Given the line: y=\dfrac43 x+1

The gradient of the line, m=\dfrac43

A line perpendicular to the given line will have a gradient, m=-\dfrac34 (by definition of perpendicularity).

Therefore, a perpendicular line that passes through the point (4,1) is:

y-y_1=m(x-x_1)\\y-1=-\dfrac34(x-4)\\y-1=-\dfrac34x+3\\y=-\dfrac34x+3+1\\y=-\dfrac34x+4

Comparing with the slope-intercept form y=mx+x, the slope of the perpendicular line, b=4.

4 0
3 years ago
Please explain this to me!
Charra [1.4K]
One meaning of a 'linear' equation is that if you draw the graph
of the equation, the graph will be a straight line.

That's an easy way to test the equation . . . find 3 points on the
graph, and see whether they're all in a straight line.

This equation is        y  =  4 / x .

To find a point on the graph, just pick any number for 'x',
and figure out the value of 'y' that goes with it.
Do that 3 times, and you've got 3 points on the graph.

Here ... I'll do 3 quick points:

Point-A:  x = 1     y =  4 / 1    =  4
Point-B:  x = 2     y =  4 / 2    =  2
Point-C:  x = 4     y =  4 / 4    =  1

Look at this:

Slope of the line from point-A to point-B
                         = (change in 'y') / (change in 'x') =  -2 .

Slope of the line from point-B to point-C
                         = (change in 'y') / (change in 'x') =  -1/2 .

The two pieces of line from A-B and from B-C don't even have
the same slope, so they're not pieces of the same straight line !
So my points A, B, and C are NOT in a straight line.

So the equation is NOT linear.

Try it again with three points of your own.
5 0
3 years ago
Write a compound inequality for the graph shown below.
irina [24]

A compound inequality for the graph would be:

x >= 0 and x < 2

7 0
4 years ago
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