Answer:
6 and 10
Step-by-step explanation:
xy=60
2(x+y)=32
x+y=16
y=16-x
Substitute y into area equation
x(16-x)=60
16x-x^2=60
x^2-16x+60=0
(x-10)(x-6)=0
x=10, 6
y=6, 10
Infinity many solutions because they both equal the same when the problem is solved.
Answer:
(C)4
Step-by-step explanation:
Given the line: 
The gradient of the line, 
A line perpendicular to the given line will have a gradient, 
(by definition of perpendicularity).
Therefore, a perpendicular line that passes through the point (4,1) is:
Comparing with the slope-intercept form y=mx+x, the slope of the perpendicular line, b=4.
One meaning of a 'linear' equation is that if you draw the graph
of the equation, the graph will be a straight line.
That's an easy way to test the equation . . . find 3 points on the
graph, and see whether they're all in a straight line.
This equation is y = 4 / x .
To find a point on the graph, just pick any number for 'x',
and figure out the value of 'y' that goes with it.
Do that 3 times, and you've got 3 points on the graph.
Here ... I'll do 3 quick points:
Point-A: x = 1 y = 4 / 1 = 4
Point-B: x = 2 y = 4 / 2 = 2
Point-C: x = 4 y = 4 / 4 = 1
Look at this:
Slope of the line from point-A to point-B
= (change in 'y') / (change in 'x') = -2 .
Slope of the line from point-B to point-C
= (change in 'y') / (change in 'x') = -1/2 .
The two pieces of line from A-B and from B-C don't even have
the same slope, so they're not pieces of the same straight line !
So my points A, B, and C are NOT in a straight line.
So the equation is NOT linear.
Try it again with three points of your own.
A compound inequality for the graph would be:
x >= 0 and x < 2
