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puteri [66]
2 years ago
7

Find the two small as possible solutions ​

Mathematics
2 answers:
solong [7]2 years ago
6 0

Answer:  \bold{b)\quad \dfrac{5}{6},\ \dfrac{25}{6}}

<u>Step-by-step explanation:</u>

12cos\bigg(\dfrac{2\pi}{5}x\bigg)+10=16\\\\\\12cos\bigg(\dfrac{2\pi}{5}x\bigg)=6\\\\\\cos\bigg(\dfrac{2\pi}{5}x\bigg)=\dfrac{1}{2}\\\\\\cos^{-1}\bigg[cos\bigg(\dfrac{2\pi}{5}x\bigg)\bigg]=cos^{-1}\bigg(\dfrac{1}{2}\bigg)

\text{Use the Unit Circle to determine when}\ cos=\dfrac{1}{2}\quad \rightarrow \quad\text{at}\ \dfrac{\pi}{3}\ and \ \dfrac{5\pi}{3}\\\\\\\dfrac{2\pi}{5}x=\dfrac{\pi}{3}\qquad and\qquad \dfrac{2\pi}{5}x=\dfrac{5\pi}{3}\\\\\\\bigg(\dfrac{5}{2\pi}\bigg)\dfrac{2\pi}{5}x=\dfrac{\pi}{3}\bigg(\dfrac{5}{2\pi}\bigg)\quad and\quad \bigg(\dfrac{5}{2\pi}\bigg)\dfrac{2\pi}{5}x=\dfrac{5\pi}{3}\bigg(\dfrac{5}{2\pi}\bigg)\\\\\\.\qquad \qquad \large\boxed{x=\dfrac{5}{6}\qquad and \qquad x=\dfrac{25}{6}}

Alla [95]2 years ago
5 0

Answer:

○ b. \displaystyle \frac{5}{6}, \frac{25}{6}

Explanation:

<em>See my above explanation</em>

I am joyous to assist you anytime. ☺️

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Step-by-step explanation:

Calculate the distance using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = E(- 2, 2) and (x₂, y₂ ) = F(4, - 6)

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2 years ago
Read 2 more answers
Nemecek Brothers make a single product on two separate production lines, A and B. Its labor force is equivalent to 1000 hours pe
frez [133]

Answer:

(a) The inequality for the number of items, x, produced by the labor, is given as follows;

250 ≤ x ≤ 600

(b) The inequality for the cost, C is $1,000 ≤ C ≤ $3,000

Step-by-step explanation:

The total time available for production = 1000 hours per week

The time it takes to produce an item on line A = 1 hour

The time it takes to produce an item on line B = 4 hour

Therefore, with both lines working simultaneously, the time it takes to produce 5 items = 4 hours

The number of items produced per the weekly labor = 1000/4 × 5 = 1,250 items

The minimum number of items that can be produced is when only line B is working which produces 1 item per 4 hours, with the weekly number of items = 1000/4 × 1 = 250 items

Therefore, the number of items, x, produced per week with the available labor is given as follows;

250 ≤ x ≤ 1250

Which is revised to 250 ≤ x ≤ 600 as shown in the following answer

(b) The cost of producing a single item on line A = $5

The cost of producing a single item on line B = $4

The total available amount for operating cost = $3,000

Therefore, given that we can have either one item each from lines A and B with a total possible item

When the minimum number of possible items is produced by line B, we have;

Cost = 250 × 4 = $1,000

When the maximum number of items possible, 1,250, is produced, whereby we have 250 items produced from line B and 1,000 items produced from line A, the total cost becomes;

Total cost = 250 × 4 + 1000 × 5 = 6,000

Whereby available weekly outlay = $3000, the maximum that can be produced from line A alone is therefore;

$3,000/$5 = 600 items = The maximum number of items that can be produced

The inequality for the cost, C, becomes;

$1,000 ≤ C ≤ $3,000

The time to produce the maximum 600 items on line A alone is given as follows;

1 hour/item × 600 items = 600 hours

The inequality for the number of items, x, produced by the labor, is therefore, given as follows;

250 ≤ x ≤ 600

8 0
3 years ago
2 find the probability of getting a sum 9 when two dice are thrown simultaneously.
Cloud [144]

Answer:

The answer is 11.1

Step-by-step explanation:

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The pharmacist uses 67mg, 100g and 0.6 kg of drug to compound 3 separate precription. how much total drug did the pharmacist use
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Answer: 700.067 g

Step-by-step explanation:

Given : The pharmacist uses 67mg, 100g and 0.6 kg of drug to compound 3 separate prescription.

We know that 1 gram= 1000 milligram

and 1 kilogram = 1000 grams

Then, By UNITARY METHOD, \text{1 mg}=\dfrac{1}{1000}\text{ gram}

Now, We convert each amount of drug into grams as ,

67\ mg=67\times\dfrac{1}{1000}\ g\\\\=0.067\text{ g}

AND

0.6\ kg=0.6\times100=60\text{ g}

Now, the total drug used by Pharmacist (in grams) = 0.067+100+600=700.067\ g

Hence, Pharmacist used 700.067 g of total drug.

8 0
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