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3 years ago

The oblique pyramid has a square base. What is the volume of the pyramid? 2.5 cm3 5 cm3 6 cm3 7.5 cm3

Mathematics

1 answer:

Olenka [21]3 years ago

3 0

Take a look at the attachment below. It fills in for the attachment that wasn't provided in the question -

An oblique pyramid is one that has a top not aligned with the base. Due to this, the height of the pyramid connects with two vertices at its ends to form a right angle present outside the pyramid, knowing that it is always perpendicular to the base. There is no difference between the calculations of the volume of an oblique pyramid and a pyramid however -

$\\Base Area = 2 cm * 2 cm = 4 cm^2,\\Volume ( Pyramid ) = 1 / 3 * ( Base Area ) * ( Height ),\\Volume = 1 / 3 * ( 4 ) * ( 3.75 ),\\-------------------------\\Volume = 5 cm^3$

<u><em>And thus, you're solution is 5 cm^3, or in other words option b!</em></u>

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Subtract and simplify. Show work please!

ra1l [238]

1) Final expression: $+7y^2-6y-17$

2) Final expression: $21x^3-46x^2+59x-30$

Step-by-step explanation:

The first expression is

$(-2y^2-11y-7)-(-9y^2-5y+10)$

First, we remove the 2nd bracket by changing the sign of all the terms inside:

$-2y^2-11y-7-+9y^2+5y-10$

Now we group the terms with same degree together:

$(-2y^2+9y^2)+(-11y+5y)+(-7-10)$

Now we solve the expression in each brackets:

$(-2y^2+9y^2)+(-11y+5y)+(-7-10)=\\+7y^2-6y-17$

So, this is the final expression.

The second expression is

$(7x-6)(3x^2-4x+5)$

We apply the distributive property, so we rewrite the expression as follows:

$(7x-6)(3x^2-4x+5)=7x(3x^2-4x+5)-6(3x^2-4x+5)$

Solving both brackets,

$7x(3x^2-4x+5)-6(3x^2-4x+5)=\\21x^3-28x^2+35x-18x^2+24x-30$

Now we group terms of same degree together:

$21x^3-28x^2+35x-18x^2+24x-30=\\21x^3+(-28x^2-18x^2)+(35x+24x)-30$

And solving each bracket,

$21x^3+(-28x^2-18x^2)+(35x+24x)-30=\\21x^3-46x^2+59x-30$

So, this is the final expression.

Learn how to simplify expressions:

brainly.com/question/7014769

brainly.com/question/11007572

brainly.com/question/11334714

#LearnwithBrainly

3 0

3 years ago

If L, M and N are midpoints of the sides of PQR, PR = 46, PQ = 40, and LN=17, find each measure

Serga [27]

Check the picture below.

let's recall that the midsegment of a triangle is the segment that's half-way to both endsides and is at the same time parallel to the 3rd side, is also half the length of the parallel side, so-called the base.

so, for example, we know L, M and N are midpoints to each segment, that means that LM is a midsegment and parallel to PR and also half the length of PR, same is true for LN and MN.