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zysi [14]
3 years ago
9

Which is the graph of the linear equality 2x-3y<12

Mathematics
1 answer:
Aloiza [94]3 years ago
8 0
2x - 3y < 12
-3y < -2x + 12...change the inequality sign because ur dividing by a negative number
y > 2/3x - 4

u have a slope of 2/3.....u have a y intercept of -4 or (0,-4)

to find the x int, sub in 0 for y and solve for x....disregard the inequality sign ....
y = 2/3x - 4
0 = 2/3x - 4
-2/3x = -4
x = -4 / (-2/3)
x = -4 * -3/2
x = 12/6
x = 2......and ur x int is 2 or (2,0)

so go ahead and plot ur intercepts (0,-4) and (2,0)....so start at (0,-4)...and since u have a slope of 2/3......go up 2 spaces and to the right 3 spaces...plot that point....then up 2 and to the right 3...plot that point...keep doing this and u will cross the x axis at (2,0)......now just draw a dashed line connecting ur plotted points

ur line will be a dashed line (because there is no equal sign in the problem)....ur shading will be above the line because it is greater then
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Answer:

Prism A:

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Prism B:

Area =250cm^2

Step-by-step explanation:

Given

See attachment for prisms

Height(h) = 10cm

Required

Determine the surface area of both prisms

Prism A is triangular and as such, the surface area is:

Area = 2 * A_b + (a + b + c) * h

Where

A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}

and

s = \frac{a + b + c}{2}

Such that a, b and c are the lengths of the triangular sides of the prism.

From the attachment;

a = 8; b =6; c =10

So, we have:

s = \frac{a + b + c}{2}

s = \frac{8 + 6 + 10}{2}

s = \frac{24}{2}

s = 12

Also:

A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}

A_b = \sqrt{12 * (12 - 8) * (12 - 6) * (12 - 10)}

A_b = \sqrt{576}

A_b = 24

So:

Area = 2 * A_b + (a + b + c) * h

Area = 2 * 24 + (8 + 6 + 10) * 10

Area = 288cm^2

Prism B is a rectangular prism. So, the area is calculated as:

Area = 2 * (ab + bh + ah)

From the attachment

a = b = 5

h =10

So:

Area =2 * (5 * 5 + 5 * 10 + 5 * 10)

Area =250cm^2

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