<span>Winning Probablity = 0.2, hence Losing Probability = 0.8
Probablity of winning atmost one time, that means win one and lose four times or lose all the times. So p(W1 or W0) = p (W1) + p(W0)
Winning once W1 is equal to L4, winning zero times is losing 5 times.
p(W1) = p(W1&L4) and this happens 5 times; p(W0) = p(L5);
p (W1) + p(W0) = p(L4) + p(L5)
p(L4) + p(L5) = (5 x 0.2 x 0.8^4) + (0.8^5) => 0.8^4 + 0.8^5
p(W1 or W0) = 0.4096 + 0.32768 = 0.7373</span>
I believe the correct answer is a hope this helps if not then sorry
Answer:
The rock hits the ground between <u>2</u> seconds and <u>2.5</u> seconds after it is dropped
Step-by-step explanation:
The given table is presented as follows;
Therefore, the rock hits the ground between t = 2 seconds and t = 2.5 seconds after it is dropped.
When n = 1, 2(1) + 1 = 3
When n = 2, 2(2) + 1 = 5
When n = 3, 2(3) + 1 = 7
When n = 4, 2(4) + 1 = 9
When n = 5, 2(5) + 1 = 11
Sum = 3 + 5 + 7 + 9 + 11 = 35
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Answer: 35
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The value of 4 in 34,258 is 4,000 times the value of 4 in 47,163 is 40,000
40,000*4,000 is 160000000
