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gogolik [260]
3 years ago
12

There are 5 slots, each containing the letters w, r, l, d or o. one letter is picked at random from each slot. what are the odds

that the letters stored in these slots read the word world?
Mathematics
1 answer:
LenaWriter [7]3 years ago
3 0
In the first slot lets calculate the chance of getting a w: 1/5

In the second slot calculate the chance of getting a o: 1/4 (notice how it's 4 not 5 because you already have one letter in the first slot so you have 4 left to choose from.)

In third slot, chance of getting a r: 1/3

In fourth slot, chance of getting a l: 1/2

In the fifth slot, if you got all the first four letters right, than you would be left with one letter, so your chances are 1/1 (100%) for the fifth slot



To calculate probability multiply all the fractions we got above: 1/5 x 1/4 x 1/3 x 1/2 x 1/1

We will then get: 1/(5x4x3x2x1) = 1/120

1/120 is the probability of the 5 slots showing the word "world"
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Los 800 am termómetro marca 2°C. De las 8 am a las 11 am baja a razón do 3C por hora y de 11 am 12pm sube a razón
Marta_Voda [28]

Answer:

28454582855%555$ ni semoga bener jawabannya

6 0
2 years ago
Please help! Will mark BRAINLIEST!
Softa [21]

your awnser was hard and complicated but i think i got it 7214.485x^10y^10

7 0
2 years ago
Please help fast will give brainliest
MrRa [10]

Answer:

MN = 160

Step-by-step explanation:

We know that arc MN = arc NO

17g - 10 = 14g+ 20

Subtract 14g from each side

3g -10 = 14g-14g+20

3g -10 =20

Add 10 to each side

3g = 20+10

3g = 30

Divide by 3

3g/3= 30/3

g= 10

We want the arc MN

17g - 10

17(10) - 10

170 -10

160

5 0
2 years ago
Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)
vagabundo [1.1K]

Answer:

Considering the given equation y = log_{3}x\\

And the ordered pairs in the format (x, y)

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For (\frac{1}{3}, a_{0} )

x=\frac{1}{3}

y=a_{0}

y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1

So the ordered pair will be (\frac{1}{3}, -1 )

For (1, a_{1} )

x=1

y=a_{1}

y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0

So the ordered pair will be (1, 0 )

For (3, a_{2} )

x=3

y=a_{2}

y = log_{3}x\\y = log_{3}3\\y = 1

So the ordered pair will be (3, 1 )

For (9, a_{3} )

x=9

y=a_{3}

y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2

So the ordered pair will be (9, 2 )

For (27, a_{4} )

x=27

y=a_{4}

y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3

So the ordered pair will be (27, 3 )

For (81, a_{5} )

x=81

y=a_{5}

y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4

So the ordered pair will be (81, 4 )

4 0
3 years ago
Scientist are studying a bacteria sample. The function f(x)=360(1.07)^x gives the number of bacteria in the sample at the end of
Lapatulllka [165]

Options :

A. The initial number of bacteria is 7.

B. The initial of bacteria decreases at a rate of 93% each day.

C. The number of bacteria increases at a rate of 7% each day.

D. The number of bacteria at the end of one day is 360.

Answer:

C. The number of bacteria increases at a rate of 7% each day.

Step-by-step explanation:

Given the function :

f(x)=360(1.07)^x ; Number of bacteria in sample at the end of x days :

The function above represents an exponential growth function :

With the general form ; Ab^x

Where A = initial amount ;

b = growth rate

x = time

For the function :

A = initial amount of bacteria = 360

b = growth rate = (1 + r) = 1.07

If ; (1 + r) = 1.07 ; we can solve for r to obtain the daily growth rate ;

1 + r = 1.07

r = 1.07 - 1

r = 0.07

r as a percentage ;

0.07 * 100% = 7%

7 0
2 years ago
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