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3 years ago

The graph above represents the following polynomial function.

Mathematics

1 answer:

Korvikt [17]3 years ago

6 0

Answer:

C. 0, -1, 3

Step-by-step explanation:

Note: There is no graph. I assume you mean "zeroes/roots" by "solutions".

x(x^2-2x-3)=0

/(x^2-2x-3)

x=0

x^2-2x-3 = x^2+x-3x-3 = x(x+1) + ( -3(x+1) = (x-3)(x+1)

/(x-3) --> x +1 =0, x=-1

/(x+1) --> x-3 = 0, x=3

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Step-by-step explanation:

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3 years ago

Write two expressions with unlike denominators whose sum is x-3/x+2, I need help it is confusing for me.

skad [1K]

Answer:

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Step-by-step explanation:

We need to find two expressions with unlike denominators what sum

$\displaystyle S=\frac{x-3}{x+2}$

Let's suppose one of the expressions is:

$\displaystyle A=\frac{x-2}{x+3}$

Now we subtract S minus A to find the other expression B:

$\displaystyle B=S-A=\frac{x-3}{x+2}-\frac{x-2}{x+3}$

Multiply the first fraction by x+3 and the second by x+2;

$\displaystyle B=(x+3)\frac{x-3}{(x+3)(x+2)}-(x+2)\frac{x-2}{(x+3)(x+2)}$

Operating:

$\displaystyle B=\frac{x^2-9}{(x+3)(x+2)}-\frac{x^2-4}{(x+3)(x+2)}$

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$\displaystyle B=\frac{x^2-9-(x^2-4)}{(x+3)(x+2)}$

Simplifying:

$\displaystyle B=\frac{-5}{(x+3)(x+2)}$

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And

$\displaystyle B=\frac{-5}{(x+3)(x+2)}$

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3 years ago