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NemiM [27]
3 years ago
14

The graph above represents the following polynomial function.

Mathematics
1 answer:
Korvikt [17]3 years ago
6 0

Answer:

C. 0, -1, 3

Step-by-step explanation:

Note: There is no graph. I assume you mean "zeroes/roots" by "solutions".

x(x^2-2x-3)=0

/(x^2-2x-3)

x=0


x^2-2x-3 = x^2+x-3x-3 = x(x+1) + ( -3(x+1) = (x-3)(x+1)

/(x-3) --> x +1 =0, x=-1

/(x+1) --> x-3 = 0, x=3


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Given the recursive function f(n) = f(n - 1) - 3 ; f(1) = 9 , what would be the first three terms of the sequence ?
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The first three terms of sequence are 9 , 6 , 3

<em><u>Solution:</u></em>

Given the recursive function f(n) = f(n - 1) - 3

Where f(1) = 9

To find: First three terms of sequence

Substitute n = 2 , n = 3 and n = 4 in given recursive function

When n = 2

f(n) = f(n - 1) - 3

f(2) = f(2 - 1) - 3

f(2) = f(1) - 3

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f(2) = 6

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When n = 3

f(3) = f( 3 - 1) - 3

f(3) = f(2) - 3

f(3) = 6 - 3 = 3

f(3) = 3

Thus the third term is 3

When n = 4

f(4) = f( 4 - 1) - 3

f(4) = f(3) - 3

f(4) = 3 - 3

f(4) = 0

Thus the fourth term is 0

Thus first three terms of sequence are 9 , 6 , 3

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