73 that will be hope this is right ok byeeee
Answer:

Step-by-step explanation:


Answer: [0,3]
The line is going up from left to right between 0 and 3 on the x-axis. We use a closed bracket because it is a open circle.
Answer:
sry im being Dumb im pretty sure its 180 because intersecting lines form vertical angles if those angles are acute the one in between is obtuve a like is 180 degrees
Answer:
3.65 through 3.74
Step-by-step explanation: