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Yuri [45]
3 years ago
10

Someone plz help me with These questions :u have to solve for x and show work

Mathematics
1 answer:
irakobra [83]3 years ago
5 0
Ok so the first one is 
1.x=135
2.x=-23
3.x=3
4.x=70

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Need help please?!?!?! Extra points!!!
andrey2020 [161]

Answer:

4.19

Step-by-step explanation:

just use the formula 2pir^2

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3 years ago
A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

6 0
3 years ago
Find the distance between the two points. (2, 4), (7, 2)
anyanavicka [17]

Answer:

5.38516480 or  √ 29

hope this helps

have a good day :)

Step-by-step explanation:

4 0
3 years ago
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HELP I NEED HELP ASAP
Julli [10]

Answer:

No spam no help

Step-by-step explanation:

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Needing help on my geometry final, I have been in and out of the hospital, any help is appreciated.
quester [9]

Answer:

1. area = 1/2bh = (1/2)(21)(18) = 189 yd²

2. 3x2x3x2 = 36 different ways

3. area of kite = (1/2)(18)(24) = 216 units²

4. 8:52  or reduced,   2:13

5. Sorry, this is not my strong point

Step-by-step explanation:

7 0
3 years ago
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