1. First, you must find the constant of variation (k). The problem indicates that t<span>he base of each triangle varies inversely with the height. So, this can be represented as below: </span> B=k/H
B is the base of the triangle (B=10). H is the height of the triangle (H=6). k is the constant of variation.
2. When you clear "k", you obtain:
B=k/H k=BxH k=10x6 k=60
3. Now, you have:
B=60/H
4. You can give any value to "H" and you will obtain the base of the second triangle.
5. If H=12, then:
B=60/H B=60/12 B=5
6. Therefore, <span>the possible base and height of a second triangle is: </span> B=5 H=12
