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3 years ago

What is the distance between the points (4, 7) and (-8, -9) in the coordinate plane

Mathematics

1 answer:

Mariulka [41]3 years ago

6 0

Answer:

$\sqrt{265} \: is \: ur \: answer \:$

I HOPE IT WILL HELP YOU.

Thank you.

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Select the correct answer.

eimsori [14]

Answer:

A. x=3, y= -6

Step-by-step explanation:

x - 2y = 15

2x + 4y= -18

Solving for x

x-2y=15

Subtract x from both sides

-2y= -x+15

Multiply both sides by -1

2y=x-15

Multiply both sides by 2

4y=2x-30

2x+4y= -18

Subtract 2x from both sides

4y= -2x-18

Combine equations:

-2x-18=2x-30

Add 2x to both sides

-18=4x-30

Add 30 to both sides

12=4x

4x=12

Divide both sides by 4

x=3

Solving for y

x-2y=15

Add 2y to both sides

x=2y+15

Multiply both sides by 2

2x=4y+30

2x + 4y= -18

Subtract 4y from both sides

2x= -4y-18

Combine equations:

-4y-18=4y+30

Add 4y to both sides

-18=8y+30

Subtract 30 from both sides

8y= -48

Divide both sides by 8

y= -6

8 0

3 years ago

For each right triangle below, find the missing side (Pythagorean’s Theorem) and the missing angle (Angle Sum theorem.)

valkas [14]

Answer:

a=21.2

n=√29

Step-by-step explanation:

$90+68.2+a=180$

$a+158.2=180$

$a=21.2$

$2^2+5^2=n^2$

$4+25=n^2$

$n^2=29$

$n=\sqrt{29}$

3 0

3 years ago

What is the solution?. 1/2x2 – x + 5 = 0

AfilCa [17]

1/2 x^2 - x + 5 = 0
Multiply through by 2 to get:
x^2 - 2x + 10 = 0
$x= \frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ; where a = 1, b = -2 and c = 10
$x=\frac{-(-2)\pm\sqrt{(-2)^2-(4\times1\times10)}}{2\times1}\\=\frac{2\pm\sqrt{4-40}}{2}\\=\frac{2\pm\sqrt{-36}}{2}\\=\frac{2\pm6i}{2}\\=1\pm3i$
Therefore, x = 1 + 3i or x = 1 - 3i

4 0

4 years ago

HELPPP brainiest for rt answer

jok3333 [9.3K]

Answer:

11.15 eleven dollars and 5 cents.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

(5x^2 - 2x - 14) - (x^2 + 4x - 10)

JulijaS [17]