Answer:
I think it's 15 students
Step-by-step explanation:
i think since 150 is half of 300 so in each class there should also be half of the people wearing red
Answer:
0.90=X or 0.89=X
If it's not right, then i'm sorry :)
Answer: 17, 13, 9, 5, 1
Step-by-step explanation:
y=-2(-2) + 9 = 13
y=-2(0) + 9 = 9
y=-2(2) + 9 = 5
y=-2(4) + 9 = 1
Answer:
We are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%
Step-by-step explanation:
We are given that in a group of randomly selected adults, 160 identified themselves as executives.
n = 160
Also we are given that 42 of executives preferred trucks.
So the proportion of executives who prefer trucks is given by
p = 42/160
p = 0.2625
We are asked to find the 95% confidence interval for the percent of executives who prefer trucks.
We can use normal distribution for this problem if the following conditions are satisfied.
n×p ≥ 10
160×0.2625 ≥ 10
42 ≥ 10 (satisfied)
n×(1 - p) ≥ 10
160×(1 - 0.2625) ≥ 10
118 ≥ 10 (satisfied)
The required confidence interval is given by

Where p is the proportion of executives who prefer trucks, n is the number of executives and z is the z-score corresponding to the confidence level of 95%.
Form the z-table, the z-score corresponding to the confidence level of 95% is 1.96







Therefore, we are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%