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posledela
3 years ago
10

HELP PLZ WILL GIVE 40 POINTS

Mathematics
1 answer:
Debora [2.8K]3 years ago
8 0

Answer:

various angles can be formed when two parallel lines are cut by a transverse line. They are :

i. Alternate Angles

ii. Corresponding angles

iii. Co interior angles

Step-by-step explanation:

i. Alternate angles are equal. In the given figure x and y are alternate angles where x=y. Similarly, w and v are also alternate angles and they are also equal in magnitude.

ii. Corresponding angles are also equal. In the given figure, a and y are corresponding angles where a=y. Similarly, b and v, w and c, x and d are corresponding angles and they are equal in value.

iii. The sum of co-interior angles is 180 degrees. In the given figure, v and x are co-interior angles where x+v= 180 degrees. Similarly, w and y are also co-interior angles and their sum is also 180 degrees.

These are the angles formed when two parallel lines are cut by a transversal line. The figure is in the attachment. You can find it there.

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There were 150 students wearing red shirts today. If there are a total of 300 students at school, about how many out of a class
alisha [4.7K]

Answer:

I think it's 15 students

Step-by-step explanation:

i think since 150 is half of 300 so in each class there should also be half of the people wearing red

3 0
2 years ago
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What is the value of x in this equation<br> [x+17]=20x
Digiron [165]

Answer:

0.90=X or 0.89=X

If it's not right, then i'm sorry :)

3 0
3 years ago
PLS I NEED HELP I’LL MARK BRAINLESS
vfiekz [6]

Answer: 17, 13, 9, 5, 1

Step-by-step explanation:

y=-2(-2) + 9 = 13

y=-2(0) + 9 = 9

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2 years ago
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Of a group of randomly selected adults, 360 identified themselves as manual laborers, 280 identified themselves as non-manual wa
Wittaler [7]

Answer:

We are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%

Step-by-step explanation:

We are given that in a group of randomly selected adults, 160 identified themselves as executives.

n = 160

Also we are given that 42 of executives preferred trucks.

So the proportion of executives who prefer trucks is given by

p = 42/160

p = 0.2625

We are asked to find the 95% confidence interval for the percent of executives who prefer trucks.

We can use normal distribution for this problem if the following conditions are satisfied.

n×p ≥ 10

160×0.2625 ≥ 10

42 ≥ 10 (satisfied)

n×(1 - p) ≥ 10

160×(1 - 0.2625) ≥ 10

118 ≥ 10 (satisfied)

The required confidence interval is given by

$ p \pm z\times \sqrt{\frac{p(1-p)}{n} } $

Where p is the proportion of executives who prefer trucks, n is the number of executives and z is the z-score corresponding to the confidence level of 95%.

Form the z-table, the z-score corresponding to the confidence level of 95% is 1.96

$ p \pm z\times \sqrt{\frac{p(1-p)}{n} } $

$ 0.2625 \pm 1.96\times \sqrt{\frac{0.2625(1-0.2625)}{160} } $

$ 0.2625 \pm 1.96\times 0.03478 $

$ 0.2625 \pm 0.06816 $

0.2625 - 0.06816, \: 0.2625 + 0.06816

(0.1943, \: 0.3306)

(19.43\%, \: 33.06\%)

Therefore, we are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%

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3 years ago
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