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SSSSS [86.1K]
3 years ago
11

How is the process of scientific inquiry

Chemistry
1 answer:
olya-2409 [2.1K]3 years ago
5 0
I don’t knowndbdjdbejanwkjbd. Dnsnsns. CNBC she enebe I
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Convert 100 miles to inches (there are 5280 ft in one mile)
expeople1 [14]

Answer:

Explanation:

100 miles * [ 5280 feet / 1 mile] * 12 inches / 1 foot]

100 * 5280 * 12 inches

6336000 inches in 100 miles

8 0
3 years ago
What volume of oxygen gas is needed to completely combust 0.202L of butane (C4H10) gas?
saveliy_v [14]

Answer:

look at the file :)

Explanation:

4 0
3 years ago
Using the model of the periodic table, which two elements pictured have similar chemical properties?
Murljashka [212]

Answer:

1 and 3

Explanation:

The vertical columns (groups) of the periodic table are arranged such that all its elements have the same number of valence electrons. All elements within a certain group thus share similar properties.

5 0
3 years ago
Read 2 more answers
Which choice correctly places the discovery of subatomic particles in order from earliest to latest?
xeze [42]
Wait hold up do you live in Wilson county????
7 0
3 years ago
What is the pH of a mixture of 0.042 M NaH2PO4 and 0.058 M Na2HPO4? Hint: The pKa of phosphate is 6.86.
AlekseyPX

Answer:

The pH value of the mixture will be 7.00

Explanation:

Mono and disodium hydrogen phosphate mixture act as a buffer to maintain pH value around 7. Henderson–Hasselbalch equation is used to determine the pH value of a buffer mixture, which is mathematically expressed as,

pH=pK_{a} + log(\frac{[Base]}{[Acid]})

According to the given conditions, the equation will become as follow

pH=pK_{a} + log(\frac{[Na_{2}HPO_{4} ]}{[NaH_{2}PO_{4}]})

The base and acid are assigned by observing the pKa values of both the compounds; smaller value means more acidic. NaH₂PO₄ has a pKa value of 6.86, while Na₂HPO₄ has a pKa value of 12.32 (not given, but it's a constant). Another more easy way is to the count the acidic hydrogen in the molecular formula; the compound with more acidic hydrogens will be assigned acidic and vice versa.

Placing all the given data we obtain,

pH=6.86 + log(\frac{0.058}{0.042})

pH=7.00

5 0
4 years ago
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