Answer:
20cm=the length of the causation that it loads about the contrasting of the solution it is an easy question to answer it just has too many parts I answered one and I hope it helped to give you a hint towards solving the whole thing good luck
Explanation:
I tried!
Answer:
The pOH of a solution that has a pH of 6.25 at 100°C is 7.75 (option D)
Explanation:
pOH + pH = 14
pOH = 14 - 6.25
pOH = 7.75
Therefore, at 100°C, the Kw of water is 5.6x10⁻¹³ and the pOH of a solution that has a pH of 6.25 at 100°C is 7.75.
Thus, option D, is the correct answer.
Answer:
it could be 25degrees c... not sure
Answer:
Energy lost is 7.63×10⁻²⁰J
Explanation:
Hello,
I think what the question is requesting is to calculate the energy difference when an excited electron drops from N = 15 to N = 5
E = hc/λ(1/n₂² - 1/n₁²)
n₁ = 15
n₂ = 5
hc/λ = 2.18×10⁻¹⁸J (according to the data)
E = 2.18×10⁻¹⁸ (1/n₂² - 1/n₁²)
E = 2.18×10⁻¹⁸ (1/15² - 1/5²)
E = 2.18×10⁻¹⁸ ×(-0.035)
E = -7.63×10⁻²⁰J
The energy lost is 7.63×10⁻²⁰J
Note : energy is lost / given off when the excited electron jumps from a higher energy level to a lower energy level
Answer : The angular acceleration is 
Solution : Given,
The given angular velocity equation is,
At t = 0, 
At t = t,
Angular acceleration : It is defined as the rate of change of angular velocity with respect to time.
Formula used for angular acceleration :
where,
= angular acceleration
= angular velocity at time 't'
= angular velocity at time '0'
t = time
Now put all the given values in this formula, we get the angular acceleration.
Therefore, the angular acceleration is
